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Natasha_Volkova [10]
3 years ago
8

 Chocolate bars come in packs of 8 and graham crackers come in packs of 12.  What is the smallest number of chocolate bars and g

raham crackers we would need to buy so we don't have any left over?  ​
Mathematics
2 answers:
Solnce55 [7]3 years ago
8 0

Answer:

3 chocolate bars, and 2 graham crackers

Someone forgot the marshmallows...... :P

Step-by-step explanation:

Chocolate bars = 8 pack

Graham Crackers = 12pack

To have no crackers or chocolate left over, we need to find LCM

Factors of 8:

8, 16, 24, 32, 40, 48, 56, 72....

Factors of 12:

12, 24, 36, 48, 60, 72

The smallest LCM is 24

Chocolate bars:

24/8 = 3

Graham Crackers:

24/12 = 2

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

9966 [12]3 years ago
7 0

Answer:

3 packs of chocolate and 2 packs of crackers

Step-by-step explanation:

the lowest common multiple of 8 and 12 is 24. We can determine this by prime factorization:

Prime factors of 8: 2 x 2 x 2

Prime factors of 12: 2 x 2 x 3

multipyling the bottom rungs of our factor tree we get: 2 x 2 x 2 x 3 = 24.

If you need me to draw the factor tree, just ask.

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This is because each position can be filled by any of the members, except for the position that the member is already filling. For example, the president can be elected from any of the 10 members, but the vice president must be elected from the remaining 9 members.

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3 0
1 year ago
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Step-by-step explanation:

Let 'X' be the Total Number of people Annette surveyed.

Out of Total people in the city, only <u>180 people are not interested</u> in a new shopping mall.

Therefore, it is given in the question that <u>180 is 37.5% of Total number of people surveyed (X).</u>

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Answer:

See possible solutions below.

Step-by-step explanation:

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cestrela7 [59]

Answer:

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Step-by-step explanation:

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