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2 years ago

Factor: 3x^(2)-16x+16

Mathematics

2 answers:

lana66690 [7]2 years ago

7 0

Answer is (3x-4) (x-4)
This is the answer for Plato and Edmentum

fenix001 [56]2 years ago

3 0

Answer:

$3 {x}^{2} - 16x + 16 \\ 3 {x}^{2} - 12x - 4x + 16 \\ 3x(x - 4) - 4(x - 4) \\ (3x - 4)(x - 4)$

Step-by-step explanation:

I hope it helped U

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After you analyzed demand, you took steps to make sure your business made sense financially.

Stells [14]

Answer:

A store ships cans by weight. A small box can hold 3 to 5 pounds. A medium box can hold 5 to 8 pounds. A large box can hold 8 to 10 pounds. The weights of the cans are given below.

Drag cans into each box to show what the box could contain.

kfeffse

Step-by-step explanation:

A store ships cans by weight. A small box can hold 3 to 5 pounds. A medium box can hold 5 to 8 pounds. A large box can hold 8 to 10 pounds. The weights of the cans are given below.

Drag cans into each box to show what the box could contain.

3 0

2 years ago

How to solve 6×+8 = 12x-4

Tatiana [17]

Answer:

x=2

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8 0

2 years ago

Ayo i need help this is vv hard or i’m jus dumb.

erastovalidia [21]

It goes straight up I hope this helps if not in sorry

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2 years ago

An electrician sent Bonnie an invoice in the amount of 'a' dollars for 6 hours of work that was done on Saturday. The electricia

Mazyrski [523]

Answer:

(a-f)/6 = r

Step-by-step explanation:

The total Bonnie must pay is the weekend fee plus the hourly rate times the hours worked

Cost = weekend fee * hourly rate* hours

hours = 6

weekend fee =f

hourly rate = r

Cost = a dollars

Substituting in what we know

a = f+ 6r

We want to solve for r

Subtract f from each side

a-f =f-f +6r

a-f = 6r

Divide each side by 6

(a-f)/6 = 6r/6

(a-f)/6 = r

4 0

3 years ago

A debate team of 4 members for a high school will be chosen randomly from a potential group of 15 students. Ten of the 15 studen

iragen [17]

Answer:

A) 0.1538

Step-by-step explanation:

4 members are going to be chosen:

M1 - M2 - M3 - M4

We have to find the probability that for each member, one without experience is chosen. There is no replacents.

Initially, we have 15 students, of which 10 have none experience. So the probability that M1 is chosen as a student with no experience is $\frac{10}{15}$ .

Then, there are 14 students, of which 9 have no experience. So the probability that M2 is chosen as a student with no experience is $\frac{9}{14}$ .

For the third member, there are 13 students, of which 8 have no experience. So the probability that M3 is chosen as a student with no experience is $\frac{8}{13}$ .

For the last member, there are 12 students, of which 7 have no experience. So the probability that M4 is chosen as a student with no experience is $\frac{7}{12}$ .

What is the probability that none of the members chosen for the team have any competition experience?

This is

$P = \frac{10}{15}*\frac{9}{14}*\frac{8}{13}*\frac{7}{12} = 0.1538$

The correct answer is:

A) 0.1538

7 0

3 years ago