Answer:
h=404.89
Step-by-step explanation:
We are looking for side h, which is opposite of the observer. We know that the side adjacent to the observer is 500 feet. We also know that the angle from the observer to the bird is 39°. Because we have these values, SOH CAH TOA tells us that we should use tangent, opposite over adjacent.
We can set up our equation as follows:
tan(39°)=h/500
We can then solve for h:
500*tan(39°)=h
h=404.89
<span>(1/3) * 4 = 4/3 = 1 and 1/3 miles</span>
Answer:
It takes 2.8 seconds for the ball to fall 215 ft.
Step-by-step explanation:
We are given a position function s(t) where s stands for the number of feet the ball has fallen, so we have to replace s with the given value of 215 ft and solve for the time t.
Setting up the equation.
The motion equation is given by

We can replace there s = 215 ft to get

Solving for the time t.
From the previous equation we can move all terms in one side to get

At this point we can solve for t using quadratic formula.

where a, b and c are the coefficients of the quadratic equation

So we get

Replacing on the quadratic formula we get

Using a calculator we get

Physically speaking the only result that makes sense is to move forward in time that give us t = 2.8 seconds.
We can conclude that it takes 2.8 seconds for the ball to fall 215 ft.
Where the rest of the question?