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svetlana [45]
3 years ago
7

5x + 1/3(3x + 6) >14

Mathematics
2 answers:
BaLLatris [955]3 years ago
5 0

Answer:

5x +  \frac{1}{3} (3x + 6) > 14   \\ lcm = 3 \\  \\ (3 \times 5x) + 3 \times  \frac{1}{3} (3x + 6) > 14 \times 3 \\  \\ 15x + 3x + 6 > 42 \\ 18x + 6 > 42 \\ 18x > 42 - 6 \\ 18x > 36 \\ x  > 2

Blizzard [7]3 years ago
4 0

Answer is below

x > 2

How I did it

What I first did was divide 3x + 6 by 3 because when you multiply by 1/3 it's basically just dividing by 3.

5x+x+2>14

Simplify

6x+2>14

Subtract 2 on both sides

6x>12

Since you want to get x by itself you divide both sides by 6, singling out x

x>2

Hope this helps!

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A company decided to test the hypothesis that the average time a company’s employees are spending to check their private e-mails
Degger [83]

Answer:

z=\frac{6.6-6}{\frac{1.7}{\sqrt{40}}}=2.232    

Since is a one sided right tailed test the p value would be:  

p_v =P(z>2.232)=0.0128  

Step-by-step explanation:

Data given and notation  

\bar X=6.6 represent the sample mean

\sigma=1.7 represent the population standard deviation

n=40 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 6minutes or no, the system of hypothesis would be:  

Null hypothesis:\mu \leq 6  

Alternative hypothesis:\mu > 6  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{6.6-6}{\frac{1.7}{\sqrt{40}}}=2.232    

P-value

Since is a one sided right tailed test the p value would be:  

p_v =P(z>2.232)=0.0128  

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It’s 17

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