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vodka [1.7K]
3 years ago
9

What is the equation of the line written in general form?

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
7 0

Answer:

option 2 or y + x -2 = 0

Step-by-step explanation:

Given a line on a graph, it is easiest to start with point-slope form.

y = mx + b

where m is the slope (rise/run) and b is the y-axis intercept.

From the plot m = -2/2 = -1 and b = 2 SO

y = mx + b

y = -x  + 2

Then the general form is

y + x -2 = 0

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Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR
erik [133]

Answer:

392

Step-by-step explanation:

Triangles XQP and YRS are right triangles because triples 6, 8, 10 are Pythagorean triples.

Extend lines XQ, YR, YS and XP and mark their intersection as A and B.

Quadrilateral XAYB is a square because all right triangles PXQ, QAR, RYS and SBP are congruent (by ASA postulate) and therefore

  • all angles of the quadrilateral XAYB are right angles
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Segment XY is the diagonal of the square XAYB, by Pythagorean theorem,

XY^2=XA^2+AY^2\\ \\XY^2=14^2+14^2\\ \\XY^2=196+196\\ \\XY^2=392  

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