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2 years ago

The angle measurements in the diagram are represented by the following expressions.

Mathematics

1 answer:

ki77a [65]2 years ago

6 0

Answer:

x=6. Angle B=126 degrees

Step-by-step

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Pleas help me solve and can you show me how you solved it

matrenka [14]

Answer: K=2

Step-by-step explanation:

-8k+6=-10k+10

+10k

2k+6=10

-6

2k=4

k=2

3 0

2 years ago

Read 2 more answers

After spending $30 on a dress, Mary had 3/8 of her money left. How much money did she have at first?

BaLLatris [955]

The answer is that she had 48. Set it up as an equation with x as the amount of money she started with. x - 30 = 3/8x. That says, in words, "the amount of money she started with minus 30 for the dress left her with 3/8 of the money she started with. Solve for x by adding 30 to both sides and subtracting 3/8 from 8/8x (8/8 = 1). 8/8 - 3/8 = 5/8, so 5/8x = 30, multiply both sides by 8 to get 5x=240 and x = 48.

3 0

3 years ago

Read 2 more answers

Help PLEASE<br><br> Match the following:

Luden [163]

Answer:

Step-by-step explanation:

mark as brain list plz and like

3 0

2 years ago

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

3 years ago

Find the whole quantity if 5 percent of it is 500

liq [111]

Answer:

10,000

Step-by-step explanation:

500/0.05= 10,000

You take the amount you are given divided by the decimal form of the percentage you are given to find the answer. It's a reverse from the way you find 5% of 10,000.

0.05=5%

Check your work: 10,000*5%= 500

5 0

2 years ago