Answer:
![2(CrO_4)^{2-} (aq) + 3N_2O(g)+ 10H^+(aq) + \longrightarrow 2Cr^{3+}(aq) + 6NO(g) + 5H_2O(l)](https://tex.z-dn.net/?f=2%28CrO_4%29%5E%7B2-%7D%20%28aq%29%20%2B%203N_2O%28g%29%2B%2010H%5E%2B%28aq%29%20%2B%20%5Clongrightarrow%202Cr%5E%7B3%2B%7D%28aq%29%20%2B%206NO%28g%29%20%20%2B%205H_2O%28l%29)
Reducing agent: nitrogen.
Oxidizing agent: chromium.
Explanation:
Hello,
In this case, the first step is to rewrite the undergoing chemical reaction indicating the oxidation state for each atom as shown below:
![(Cr^{+6}O^{-2}_4)^{2-} (aq) + N^+_2O^{-2}(g)+ H^+(aq) + OH^-(aq) + H_2O(l) \longrightarrow Cr^{3+}(aq) + N^{+2}O^{-2}(g) + H^+(aq) + OH^-(aq) + H_2O(l)](https://tex.z-dn.net/?f=%28Cr%5E%7B%2B6%7DO%5E%7B-2%7D_4%29%5E%7B2-%7D%20%28aq%29%20%2B%20N%5E%2B_2O%5E%7B-2%7D%28g%29%2B%20H%5E%2B%28aq%29%20%2B%20OH%5E-%28aq%29%20%2B%20H_2O%28l%29%20%5Clongrightarrow%20Cr%5E%7B3%2B%7D%28aq%29%20%2B%20N%5E%7B%2B2%7DO%5E%7B-2%7D%28g%29%20%2B%20H%5E%2B%28aq%29%20%2B%20OH%5E-%28aq%29%20%2B%20H_2O%28l%29)
In such a way, we observe the following half-reactions:
* Reduction as chromium undergoes a decrease in its oxidation state:
![(Cr^{+6}O_4^{-2})^{2-}+8H^++3e^-\rightarrow Cr^{+3}+4H_2O](https://tex.z-dn.net/?f=%28Cr%5E%7B%2B6%7DO_4%5E%7B-2%7D%29%5E%7B2-%7D%2B8H%5E%2B%2B3e%5E-%5Crightarrow%20Cr%5E%7B%2B3%7D%2B4H_2O)
* Oxidation as nitrogen undergoes an increase in its oxidation state:
![N^+_2O^{-2}+H_2O\rightarrow 2N^{+2}O^{-2}+2H^++2e^-](https://tex.z-dn.net/?f=N%5E%2B_2O%5E%7B-2%7D%2BH_2O%5Crightarrow%202N%5E%7B%2B2%7DO%5E%7B-2%7D%2B2H%5E%2B%2B2e%5E-)
In such a way, we state that the nitrogen is the reducing agent as it is oxidized and chromium the oxidizing agent as it is reduced, therefore, the balanced chemical reaction turns out:
![2(CrO_4)^{2-} (aq) + 3N_2O(g)+ 10H^+(aq) + \longrightarrow 2Cr^{3+}(aq) + 6NO(g) + 5H_2O(l)](https://tex.z-dn.net/?f=2%28CrO_4%29%5E%7B2-%7D%20%28aq%29%20%2B%203N_2O%28g%29%2B%2010H%5E%2B%28aq%29%20%2B%20%5Clongrightarrow%202Cr%5E%7B3%2B%7D%28aq%29%20%2B%206NO%28g%29%20%20%2B%205H_2O%28l%29)
Best regards.
Answer:
ok Look at it and tell me if you think its correct :}
When you burn paper you are chemically altering it so that is the correct answer. When you do all the other choices all of the components stay the same. Just because it changes shapes doesn't mean it'll change chemically toom
A. 8,330 --> 8.33 × 10^3
B. 83.3 --> 8.33 × 10^1
C. 0.00833 --> 8.33 × 10^-3
D. 0.0833 --> 8.33 × 10^-2
E. 83,330 --> 8.33 × 10^4
Hope this helps!