Answer:
0.18 ; 0.1875 ; No
Step-by-step explanation:
Let:
Person making the order = P
Other person = O
Gift wrapping = w
P(p) = 0.7 ; P(O) = 0.3 ; p(w|O) = 0.60 ; P(w|P) = 0.10
What is the probability that a randomly selected order will be a gift wrapped and sent to a person other than the person making the order?
Using the relation :
P(W|O) = P(WnO) / P(O)
P(WnO) = P(W|O) * P(O)
P(WnO) = 0.60 * 0.3 = 0.18
b. What is the probability that a randomly selected order will be gift wrapped?
P(W) = P(W|O) * P(O) + P(W|P) * P(P)
P(W) = (0.60 * 0.3) + (0.1 * 0.7)
P(W) = 0.18 + 0.07
P(W) = 0.1875
c. Is gift wrapping independent of the destination of the gifts? Justify your response statistically
No.
For independent events the occurrence of A does not impact the occurrence if the other.
Thickness of the plate before polishing = 2.342
Thickness of the plate after polishing. = 2.087
How much was removed = 2.342- 2.087 = 0.255
Hence , the answer 0.255 which is option B
Answer: I think its B or C bc if you subtract them on the 180 you will get the same answer and by just adding them back again.
Step-by-step explanation:
Answer:
A. (2,-0.5)
Step-by-step explanation:
A pair of coordinates is always (x,y) so
If you insert the numbers into the equation you get
10(-0.5) = 3(2) - 11
-5 = 6 - 11
-5 = -5
Therefore (2,-0.5) is the point that likes on the graph
Answer:
FG = 15
Step-by-step explanation:
Note that
EF + FG = EG ← substitute values into equation, that is
6 + FG = 21 ( subtract 6 from both sides )
FG = 21 - 6 = 15
