Answer:
percent (%) of ancient prehistoric thinner than 3 is 0.0013
Step-by-step explanation:
Given data
mean = 5.1 millimeters (mm)
standard deviation = 0.7 mm
to find out
percent (%) of ancient prehistoric thinner than 3
solution
we have given mean and SD
so Z will be = x -mean / SD
Z = ( x - 5.1 ) / 0.7
so P( x < 3 ) = P ( (x - 5.1 ) / 0.7 < ( 3 - 5.1 ) / 0.7 )
P( Z = ( 3 - 5.1 ) / 1.5 )
P( Z = -3 ) = 0.0013
percent (%) of ancient prehistoric thinner than 3 is 0.0013
I guess that is 1:10
Hope ur help !;(
In a rhombus opposite angles are equal and all 4 add up to 360
assuming one angle is 53, the opposite angle will also be 53 and then adjacent angles will be (360 - (53 x 2))/2 = 254/2 = 127*(deg)
I think the answer you're looking for is 127
