<u>Part</u><u> </u><u>(</u><u>i</u><u>)</u>
1) AB is perpendicular to BC, ED is perpendicular to CD, BC = CD (given)
2) Angles ABC and CDE are right angles (perpendicular lines form right angles)
3) Angles ABC and CDE are equal (all right angles are equal)
4) Angles ACB and DCE are equal (vertical angles are equal)
5) Triangles ABC and EDC are congruent (ASA)
<u>Part</u><u> </u><u>(</u><u>ii</u><u>)</u>
6) AB = DE (corresponding parts of congruent triangles are equal)
Plug in 6.5 for x.
-8.5x-3.5x=-78
-8.5(6.5)-3.5(6.5)=-78
-55.25-22.75=-78
-78=-78
ill help but where is the clock?
To solve this problem you must apply the proccedure shown below:
1. You have that the following information given in the problem above: The<span> photograph is reduced by a scale factor of 3/8 and the original had a length of 20 inches,
2- Therefore you have:
length=20 inches-</span>(20 inches x 3/8)<span>
length=20 inches-7.5 inches
length=12.5 inches
3- Then, as you can see, the answer is: 12.5 inches.</span>
Positive product:
(-2/5)(-2/5)
(2/5)(2/5)
negative product:
(-2/5)(2/5)
(2/5)(-2/5)