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weeeeeb [17]
3 years ago
13

I NEED HELP ASAP PLSSS

Mathematics
2 answers:
Triss [41]3 years ago
5 0

Answer:

y = x^2 - 4x - 5

y = (x + 1)(x - 5)

Lena [83]3 years ago
4 0

Answer:

Standard \: form :\:y=  {x}^{2}  - 4x - 5\\Factored\: from:\:y = (x  + 1) (x - 5)

Step-by-step explanation:

y = (x - 2)^{2}  - 9 \\  y=  {x}^{2}   - 4x + 4 - 9 \\   \red{ \boxed{ \bold{y=  {x}^{2}  - 4x - 5}}} \\ is \: in \: standard \: form \\  \\ y = (x - 2)^{2}  - 9  \\ y =  (x - 2)^{2}  -  {3}^{2}  \\ y =  \{(x - 2) + 3\} \{(x - 2) - 3 \} \\ y = \{x - 2 + 3\} \{x - 2- 3 \} \\ \purple{ \boxed{ \bold{y = (x  + 1) (x - 5)}}} \\ is \: in \: factored \: form

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dangina [55]

Using pythagorean identities,tan(sin^-1(-5/13))= tan(arcsin(-5/13))

Let A = arcsin(-5/13) = -arcsin(5/13)

Thus, sin A = -5/13 and cos A = sqrt(1 - (5/13)^2) = 12/13.= tan(A)= sin(A) / cos(A)= -5/13 / (12/13)= -5/12


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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