Which number is irrational? A. 75 B. 5√ C. 7.356 D. -3

How do you concert percent into fractions in simple form

Rasek [7]

You have to convert the percent into a decimal before you convert it into a fraction then you simplify the fraction.
Hope this helps! :)

5 0

3 years ago

Consider the quadratic equation ax^2+bx+5=0,where a, b and c are rational numbers and the quadratic has two distinct zeros.

FrozenT [24]

You have shared the situation (problem), except for the directions: What are you supposed to do here? I can only make a educated guesses. See below:

Note that if ax^2+bx+5=0 then it appears that c = 5 (a rational number).

Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers. If this is the case, then the discriminant, b^2 - 4(a)(c), must be positive. Since c = 5,

b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.

Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then

(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,

- b plus sqrt( b^2 - 20a )
d = ------------------------------------
2a

and

 - b minus sqrt( b^2 - 20a )
e = ------------------------------------
2a

Some (or perhaps all) of these facts may help us find the values of "a" and "b." Before going into that, however, I'm asking you to share the rest of the problem statement. What, specificallyi, were you asked to do here?

7 0

3 years ago

PLEEASE COME TO MY CLASS AND CRASH IT WITH DN JOKES OR MUSIC

Grace [21]

Ok bet I got you say less

3 0

3 years ago

Read 2 more answers

There are 4 cards in the box with the numbers 2, 5, 6, and 8. Two cards are drawn one after the other. The second card drawn is

malfutka [58]

It is given that there are 4 cards with numbers 2, 5, 6, and 8.

1) It is required to list all the numbers available when two cards are drawn one after the other and the second card is placed at the right of the first card drawn.

To do this, find the sample space of the draw which are:

$25,26,28,52,56,58,62,65,68,82,85,86$

Hence, the required numbers.

2) Recall that probability is the ratio:

$Probability=\frac{\text{ number of favorable outcomes}}{\text{ total number of possible outcomes}}$

From the numbers listed, notice that the total number of possible outcomes is 12.

Since event A is "obtained number is even", notice that the number of even numbers in the listed numbers is 9 (26,28,52,56,58,62,68,82,86).

Hence, the number of favorable outcomes is 9.

Substituting into the probability ratio gives the required probability:

$P(A)=\frac{9}{12}=\frac{3}{4}$

Check the number of numbers that are a multiple of 5, notice that they are 3 (25,65,85).

Hence, the required probability of event B is:

$P(B)=\frac{3}{12}=\frac{1}{4}$

The number of multiple of 3 in the listed numbers is 0 since there is no number that is a multiple of 3.

Hence, the required probability of event C is:

$P(C)=\frac{0}{12}=0$

Answers:

1) {25,26,28,52,56,58,62,65,68,82,85,86}

2) P(A) = 3/4

P(B) = 1/4

P(C)= 0

7 0

1 year ago

A rectanglelar field has an area of 2100 square feet. The length of the field is 50 feet

Setler [38]

Answer: 42 feet

Step-by-step explanation:

P-area of field

P=2100sqf

a-length of field

a=50 feet

P=a*b

2100sqf=50*b

b=2100/50

b=42 feet

5 0

3 years ago