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s2008m [1.1K]
3 years ago
12

Which number is irrational? A. 75 B. 5√ C. 7.356 D. -3

Mathematics
1 answer:
mylen [45]3 years ago
5 0
B. is an irrational number i think
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Please help i have no idea how to answer this
BabaBlast [244]
Answer: 1/32
Multiple 1/4 x 1/8 to get your answer
4 0
2 years ago
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What is 7 8/13 rounded to the nearest whole number?
vfiekz [6]

Answer: The answer would be 8.

Step-by-step explanation: I'm going to assume you mean 7 8/13 is a mixed fraction. So you multiply the denominator, 13, multiply 7 to that, then add 8 to it and the denominator would be the same as before. That should give you 99/13. When you divide, you get around 7.6, rounding closest to 8.  

6 0
3 years ago
Put the following equation of a line into slope-intercept form, simplifying all
dmitriy555 [2]

Answer:

Brainliest!

Step-by-step explanation:

slope intercept form is in: y = mx + b

12y = -8x + 48

y = (-8x+48)/12

y = -2/3x+4

3 0
2 years ago
Original Price: $22.56 Tax: 7.3% Final Price
Colt1911 [192]

Just take 7.3% of 22.56, and add it to the total cost

$24.21

To find the percentage of a number, Multiply the number by the percent, divide by 100, round.

8 0
3 years ago
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How to find function definition area
insens350 [35]

Answer:Definition area"? Do you mean the "natural domain" of the function- the region in which the formula is defined? In order that a number have a square root that number must be non-zero.

Step-by-step explanation:Here, we must have x−1x≥0.

If x is positive, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, both x- 1 and x+ 1 must have the same sign: either x-1> 0 and x+ 1> 0 or x- 1< 0 and x+ 1< 0. The first pair of inequalities is true for x> 1 and the second for x< -1. Since "x is positive", we must have x> 1.

If x is negative, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, x- 1 and x+ 1 must have opposite signs: x+ 1> 0 and x- 1< 0 or x- 1<0 and x- 1> 0. The first pair is true for −1≤0≤1. The second pair are never both true. Since "x is negative" we must have −1≤x≤0.

Of course, we also cannot divide by 0 so x= 0 is not in the domain. The domain is the union of the two separate sets:{x|−1≤x<0}∪{x|x>1}.

Hope That Helps!

8 0
3 years ago
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