The slope of a line that is perpendicular to the line y = 8x + 5 will be -1/8.
<h3>What is the slope of perpendicular lines?</h3>
Suppose that first straight line has slope 's'
Let another straight line be perpendicular to this first line.
Let its slope be 'a'
Then due to them being perpendicular, they have their slopes' multiplication as -1
or
s x a = -1
s = -1/ a
Slope of line y = 8x + 5
s = 8
The slope of a line that is perpendicular to the line y = 8x + 5
8 x a = -1
a = -1/8
Thus, the slope is -1/8.
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The equation you had:
6x + 5y = 45
Solve for Y:
5y = (-6x) + 45 divide by 5
y = (-6/5)x + 9
y = -1 1/5x +9
Answer:
40 miles
Step-by-step explanation:
10X4
The correct equation should look something like this:
y= -1x - 2
Consider the equation for a line:
y = mx + b,
Where ‘m’ is the slope
Where ‘b’ is the y-intercept.
From there you can plug in your known values for ‘m’ and ‘b’, and get the equation above. If you are still not convinced, I suggest you graph the function and observe its slope and y-intercept.
Hope this helps!