3 years ago

Solve: k^2+5k-6=0 using the quadratic formula

Mathematics

1 answer:

7nadin3 [17]3 years ago

4 0

Answer:

k = 1 or k = -6

Step-by-step explanation:

k² + 5k -6 = (K-1) (k+6) = 0

k = 1 or k = -6

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The simplified expression of $\frac{x^3 + (-y)^3}{(x - y}$ is $x^2+xy+y^2$

<h3>Complete question</h3>

Simplify the expression: (x³ + (-y)³) / (x - y)

Do not include parentheses in your answer.

<h3>How to simplify the expression?</h3>

The expression is given as:

$\frac{x^3 + (-y)^3}{(x - y}$

Open the inner bracket

$\frac{x^3 -y^3}{(x - y}$

Apply the difference of two cubes to the numerator

$\frac{(x-y)(x^2+xy+y^2)}{(x - y}$

Cancel out the common factors

$x^2+xy+y^2$

Hence, the simplified expression of $\frac{x^3 + (-y)^3}{(x - y}$ is $x^2+xy+y^2$