Answer:
The answer is d
Step-by-step explanation:
Answer:
209.22cm²
Step-by-step explanation:
A=πrl+πr2
l=r2+h2
Solving forA
A=πr(r+h2+r2)=π·4·(4+122+42)≈209.21889cm²
Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Answer:
The new coordinate of B' will be ( -1, 6)
