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dlinn [17]
2 years ago
8

Which expression represents -8x^2+54x+140 in factored form?

Mathematics
1 answer:
Elenna [48]2 years ago
7 0

Answer:

D. (x+2)(-8x+70)​

Step-by-step explanation:

-8x^2+54x+140

Factor out -2

-2(4x^2+27x+70)

Factor

-2(x+2)(4x-35)

Option D is the same answer if we multiply -2 in the second term

(x+2) (-8x+70)

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Which letter represents the equation for the table of values? f(x) = 5(13)x B. f(x) = 3(15)x C. f(x) = 3(5)x D. f(x) = 5(3)x
OLga [1]

Answer:

can I see the table of values

5 0
2 years ago
There are 97 students in South High School. South High School offers only Chinese and Spanish. There are 5 more students in Chin
Viefleur [7K]

Answer:

5

Step-by-step explanation:

Spanish: 46

Chinese: 51

Both languages: 46 - 41 = 5

Hope this helps

8 0
2 years ago
A) y = 5x<br><br>B) y = 10x<br><br>C) y = 7.5x<br><br>D) y = 30x​
Jet001 [13]
Y=30x is the answer to this
5 0
2 years ago
Find the average rate of change for the equation [1,6] f(x)=-ln(x)
Irina18 [472]
The average rate of change for a function f(x) at two different values of x can be calculated by the following formula:

\frac{f( x_{2})-f( x_{1})}{ x_{2} - x_{1} }

We are to find the find the average rate of change of given function over the range [1,6], so,

x_{1}=1 \\ &#10; x_{2}=6

Using the values in above formula, we get:

\frac{f(6)-f(1)}{6-1}  \\  \\ &#10;= \frac{-ln(6)-(-ln(1))}{5} = \frac{-ln(6)-0}{5}  \\  \\ &#10;= \frac{-ln(6)}{5}

Thus the average rate of change for f(x) = -ln(x) for the interval [1,6] is given by the above expression

7 0
3 years ago
A boat sails on a bearing of 63 for 124 miles and then turns and sails 201 miles on a bearing of 192. Find the distance of the b
zzz [600]

The distance of the boat from its starting point is 156.226 .

According to the question

A boat sails on a bearing of 63 degree for 124 miles

i.e

By making 63 degree covers 124 miles

therefore ,

In figure below

AC = 124 miles

Then turns and sails 201 miles on a bearing of 192 degree

therefore ,

In figure below

CD = 201 miles  

Now,

According to the sum of triangle

∠ACB + ∠ABC + ∠BAC = 180°

∠ACB + 90° + 63° = 180°

∠ACB = 27°

CE = 180°  (Straight line )

therefore,

∠DCE = 192°  -  180°

          = 12°

As ∠C = 90°

therefore

∠ACD = ∠C - ∠DCE - ∠ACB

          = 90° - 12°- 27 °

          = 51°

Now,

The distance of the boat from its starting point = AD

By using Law of Cosines

As

The Law of Cosines can be used to find the unknown parts of an oblique triangle(non-right triangle), such that either the lengths of two sides and the measure of the included angle is known (SAS) or the lengths of the three sides (SSS) are given.

The Law of Cosines (also called the Cosine Rule) says:

c² = a² + b² − 2ab cos(C)

As we have 2 sides and one angle available we can use   Law of Cosines

Therefore,

by substituting the value

(AD)² = (AC)² + (CD)² − 2(AC)(CD) cos(∠ACD)

(AD)² = (124)² + (201)² − 2*124*201 cos(51)

AD = 156.226

Hence, the distance of the boat from its starting point is 156.226 .

To know more about Law of Cosines here:

brainly.com/question/17289163

#SPJ4

3 0
2 years ago
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