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Ilya [14]
3 years ago
5

Shirley graphed the line shown on the coordinate plane

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0
But this is not a question. proof? no question mark

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Write the fraction as a whole or mixed number.
Wewaii [24]

Answer:

1\frac{1}{2}

Step-by-step explanation:

If there is 1500 cellular phones per 1000 people, then the number of phones per person is:

\frac{1500}{1000} = \frac{15}{10} = \frac{3}{2}

Now we know that \frac{3}{2} = 1 + \frac{1}{2} = 1\frac{1}{2}

5 0
3 years ago
Update:
ohaa [14]

Answer:

Love vines!

Step-by-step explanation:

But vine left us while getting milk. And tick tock is like our step father that we've grew to love :)

4 0
3 years ago
Read 2 more answers
Can someone help me with these both
Anna [14]
Hello,
so all you have to do is match the abbreviations to the triangles. The abbreviations stand for what is the SAME in both triangles, denoted by similar markings on equal sides and angles.

Abbreviations:
SSS = Side-Side-Side
SAS = Side-Angle-Side
ASA = Angle-Side-Angle
AAS = Angle-Angle-Side
HL = Hypotenuse-Leg

* Note - the angle side angle must go around the triangle in that order. ASA has the side BETWEEN the congruent angles.. SSA does NOT work.

(9.) ASA
(10.) AAS
(11.) SSS
(12.) No way to tell if congruent. (only 3 angles no side)
(13.) ASA
(14.) SAS
(15.) HL

7 0
3 years ago
Help please please !!!!!!!
lyudmila [28]
In each case, you can use the second equation to create an expression for y that will substitute into the first equation. Then you can write the result in standard form and use any of several means to find the number of solutions.

System A
  x² + (-x/2)² = 17
  x² = 17/(5/4) = 13.6
  x = ±√13.6 . . . . 2 real solutions

System B
  -6x +5 = x² -7x +10
  x² -x +5 = 0
The discriminant is ...
  D = (-1)²-4(1)(5) = -20 . . . . 0 real solutions

System C
  y = 8x +17 = -2x² +9
  2x² +8x +8 = 0
  2(x+2)² = 0
  x = -2 . . . . 1 real solution
7 0
3 years ago
Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m
laila [671]
Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of t_{ \frac{1}{2} } after t years is given by

N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\  \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\  \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\  \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>
5 0
3 years ago
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