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frutty [35]
3 years ago
13

A cyclist cycles a distance of 40 miles in a time of 2 hours. what is her average speed?

Mathematics
1 answer:
snow_lady [41]3 years ago
6 0

Answer:

see this and it by your own

Step-by-step explanation:

How do you find average speed with distance and time?

Divide the distance by the time.

This will give you the average speed per unit of time, usually hour. So, if Ben traveled 150 miles in 3 hours, his average speed is 50 miles per hour

How do you find average speed with hours and minutes?

How to calculate average speed. Speed is distance divided by time. Simply put, if you drove 60 kilometer's for one hour, it would look like this: Speed = distance (60 km) / time (1 hour) = 60km/h.

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a rental car costs $26 per day plus $0.30 per mile. if someone has $350 to spend and needs to drive the car 60 miles each day, f
SVEN [57.7K]
If u have to drive the car 60 miles per day, at 0.30 per mile, then u r spending 
(60 x 0.30) = 18 per day on just driving.

plus the 26 per day for the rental

totals : 18 + 26 = 44 per day

44d = 350
d = 350/44
d = 7.95 rounds to 8 days

answer is 8 days
5 0
3 years ago
Read 2 more answers
Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9
nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B  

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = \left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]  = 1(1-4) - 2(2-6) + 3(4 - 3)

                    = 1(-3) - 2(-4) + 3(1)

                    = -3+8+3 = 8

also D\neq 0

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

Dx =  \left[\begin{array}{ccc}11&2&3\\10&1&2\\9&2&1\end{array}\right]   = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16

x = \frac{Dx}{D}  = \frac{16}{8} = 2

similarly

Dy = \left[\begin{array}{ccc}1&11&3\\2&10&2\\3&9&1\end{array}\right] = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0

y = \frac{Dy}{D} = 0

Dz= \left[\begin{array}{ccc}1&2&11\\2&1&10\\3&2&9\end{array}\right] = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24

z = \frac{Dz}{D} = \frac{24}{8} = 3

so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

3 0
3 years ago
(1,5) (-2,-2) slope?? help im dum
jek_recluse [69]

Answer:

Slope is 7/3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
(2x+0.5)2–(2x–0.5)2 for x=−3.5
kenny6666 [7]
Just substitute wherever x is for example 2 times 3.5
6 0
3 years ago
One fish is 4 feet below sea level anther fish is 3 feet below sea level. writhe each position as an interger
Klio2033 [76]
4 ft below sea level : -4
3 ft below sea level : -3
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3 years ago
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