All categories

2 years ago

Can somebody help me please-

Mathematics

1 answer:

arsen [322]2 years ago

3 0

Answer:

Step-by-step explanation:

volume=9×3×4+6×3×4+3×3×4=(9+6+3)×3×4=18×12=216 yd³

You might be interested in

$24,000 for new Honda, 2.75% interest rate for 4 years. What is the monthly payment? ( Explanation needed)

noname [10]

2.75/100=0.0275
= 24000 x ( 1 + 0.0275 ) ^ 4= 26750.91
26750.91 - 24000 = 2750.90
i’m sorry if it’s wrong

7 0

2 years ago

Read 2 more answers

Calculate S30 for the arithmetic sequence defined by {an}={3.1n-2}

timurjin [86]

Answer:

c) 1,381.5.

Step-by-step explanation:

First term = 3.1 *1 - 2 = 1.1

2nd term = 3.1*2 - 2 = 4.2

3rd term = 3.1*3 - 2 = 7.3

so the common difference d = 3.1.

S30 = (30/2) [ 2* 1.1 + (30-1) * 3.1)]

= 1,381.5.

3 0

2 years ago

Identify the maximum or minimum value and the domain and range of the graph of the function y = 2(x – 3)2 – 4.

NISA [10]

We are given the equation y = 2(x – 3)^2 – 4 and is asked for the domain and range of the following function. In this case, there is no radical sign so the domain includes all real numbers. The range has a minimum value of -4 since the squaring makes the value on the first term positive. Hence the answer is A.

3 0

3 years ago

Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0

skad [1K]

$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

$\bf 6rsin(\theta)\iff 2\cdot r\cdot \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}
\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

$\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\
\left. \qquad \right.\uparrow \\
\textit{so-called "completing the square"}
\\\\\\\
[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)
\\\\\\
r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)$

3 0

3 years ago

Graph y=6x−7<br> Identify the x-intercept.

valina [46]

9514 1404 393

Answer:

x-intercept: 7/6

Step-by-step explanation:

The x-intercept is found by solving for x when y=0.

0 = 6x -7

7 = 6x . . . . . add 7 to both sides of the equation

7/6 = x . . . . divide both sides by 6

The x-intercept is 7/6 = 1 1/6 ≈ 1.167.

The y-intercept is the constant in the given equation: -7. The slope of 6 tells you the line rises 6 units for 1 unit to the right. So, the point (1, -1) is another point on the graph. The line through those two points, (0, -7) and (1, -1), will intersect the x-axis at x=7/6.

6 0

3 years ago