Answer:
By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single
Step-by-step explanation:
let p1 be the proportion of elementary teachers who were single
let p2 be the proportion of high school teachers who were single
Then, the null and alternative hypotheses are:
: p2=p1
: p2>p1
We need to calculate the test statistic of the sample proportion for elementary teachers who were single.
It can be calculated as follows:
where
- p(s) is the sample proportion of high school teachers who were single (
) - p is the proportion of elementary teachers who were single (
)
- N is the sample size (180)
Using the numbers, we get
≈ 1.88
Using z-table, corresponding P-Value is ≈0.03
Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)
Answer:
x = 7
y = 0
Step-by-step explanation:
Close, but not quite.
Answer:
Just tried this on a calculator
)) i think its 7/2!
Step-by-step explanation:
Would it be 2.5??? I think it would but not completely sure
Answer:
The answer to your question is -27/20
Step-by-step explanation:
Divide 3/5 ÷ - 4/9
Process
1.- Just multiply the numerator of the first fraction by the denominator of the second fraction.
3 x - 9 = -27
2.- Multiply the denominator of the first fraction by the numerator of the second fraction.
5 x 4 = 20
3.- Join both results
-27/20