Answer:
O The number of ounces is graphed on the y-axis, and the number of quarts is graphed on the x-axis.
Step-by-step explanation:
This was a multiple choice question right?
I believe O The number of ounces is graphed on the y-axis, and the number of quarts is graphed on the x-axis. is the answer.
Answer:
a) A. The population must be normally distributed
b) P(X < 68.2) = 0.7967
c) P(X ≥ 65.6) = 0.3745
Step-by-step explanation:
a) The population is normally distributed having a mean (
) = 64 and a standard deviation (
) = 
b) P(X < 68.2)
First me need to calculate the z score (z). This is given by the equation:
but μ=64 and σ=19 and n=14, 
and 
Therefore: 
From z table, P(X < 68.2) = P(z < 0.83) = 0.7967
P(X < 68.2) = 0.7967
c) P(X ≥ 65.6)
First me need to calculate the z score (z). This is given by the equation:
Therefore: 
From z table, P(X ≥ 65.6) = P(z ≥ 0.32) = 1 - P(z < 0.32) = 1 - 0.6255 = 0.3745
P(X ≥ 65.6) = 0.3745
P(X < 68.2) = 0.7967
To answer this question you will find the means and the mean absolute deviations and compare them.
The correct answers are
A and C.
Please see the attached picture for the organized work.
Answer: <span><span>the domain of g [f(x) ] is the set of all real values except 7 and the x for which f(x) = - 3.</span>
Explanation:
Taking (g•f)(x) as (g o f) (x), this is g (x) composed with f(x) you have this analysis.
(g o f) (x) is g [ f(x) ], which means that you first apply the function f and then apply the function g to the output of f(x).
The domain of g [ f(x) ] has to exclude 7, because it is not included in the domain of f(x).
Also the domain thas to exclude those values of x for which f(x) is - 3, because the domain of g(x) is the set of all real values except - 3.
So, the domain of g [f(x) ] is the set of all real values except 7 and the x for which f(x) = - 3.
</span>
Answer:
Step-by-step explanation:
Remark
Simple answer: you can't. I mean that you can't try to use 4 numbers, but you can solve the problem. You are going to have to redraw the diagram on another sheet of paper. Follow the directions below.
Directions for diagram extension.
Go to the right hand end of the 10 unit line.
Draw a line from the intersection point of the 10 unit line and 12 unit line
Draw this line so it is perpendicular to the 18 unit line. That will mean that the new line is parallel (and equal) to x
Mark the intersect point of the new line and the 18 unit line as B
Mark the intersect point of the 18 point line and the 12 unit line as C
Given and constructed
BC = 18 - 10 = 8
BC is one leg of the Pythagorean triangle.
The new x is the other leg of the Pythagorean triangle.
12 is the hypotenuse.
Formula
x^2 + 8^2 = 12^2
x refers to the new x which is equal to the given x
Solution
x^2 + 64 = 144 Subtract 64 from both sides
x^2 +64 - 64 = 144-64 Combine
x^2 = 80 Break 80 down.
x^2 = 4 * 4 * 5 Take the square root of both sides
x = 4*sqrt(5)
Comment
If you want the area it is 4*sqrt(5)(10 + 18)/2 = 56*sqrt(5)
