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givi [52]
2 years ago
7

In the function f(x) = 4(x2 − 6x + ____) + 20, what number belongs in the blank to complete the square?

Mathematics
1 answer:
Oxana [17]2 years ago
7 0

Answer:

9

Step-by-step explanation:

6x=2*x*(a number), (a number)^2=the number we need. A number=3, the number is 3^2=9

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Q + 5/9= 1/6 from big ideas mathbook
Alika [10]
9We have such eqation
Q+ \frac{5}{9} = \frac{1}{6}    /*9   (multiply both sides by 9)
9Q+5=\frac{9}{6}    /-5 both sides
9Q=\frac{9}{6}- 5
9Q=\frac{9}{6}- \frac{5*6}{6}
9Q=\frac{9-30}{6}
9Q=-\frac{21}{6}        /:9 divide both sides by 9
Q=-\frac{21}{6}:9
Q\frac{21}{6*9} =- \frac{21}{54}=[tex] \frac{7}{18} - its the answer
6 0
3 years ago
Read 2 more answers
Someone please help with this !!!!!
dolphi86 [110]

Answer:

[[[[[[[[[[[[[[[[

Step-by-step explanation:

oooo[

6 0
2 years ago
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If f(x)= x2 + 2 and g(x)= 2x-1, find (f ° g)(5).
valentinak56 [21]
I hope this helps you

4 0
3 years ago
Write -4i+(1/4-5i)-(-3/4+8i)+17i as a complex number in the standard for
KatRina [158]

Answer:

1+ 0i

Step-by-step explanation:

A complex number is a number which has some real part and some imaginary part.

Standard form of a complex number is represented as

a +bi

Where a is the real part,

and bi is the imaginary part.

And i = \sqrt{-1}

Given complex number:

-4i+\dfrac{1}{4}-5i)-(-\dfrac{3}{4}+8i)+17i\\\Rightarrow -4i+\dfrac{1}{4}-5i + \dfrac{3}{4}-8i+17i\\\Rightarrow  \dfrac{3}{4}+\dfrac{1}{4}-4i -5i-8i+17i\\\Rightarrow  \dfrac{3+1}{4}-17i+17i\\\Rightarrow \dfrac{4}{4}+0i\\\Rightarrow 1 + 0i

Hence, the standard form is 1+ 0i.

8 0
2 years ago
ONLY SERIOUS ANSWERS!!!! 25 POINTS
AveGali [126]

Answer:

FD≈25.94.. rounded = 26

Step-by-step explanation:

FD²=12²+(4x+11)²

FD²=144+16x²+88x+121

FD²=265+16x²+88x

also

FD²=12²+(13x-16)²

FD²=144+169x²-416x+256

FD²=400+169x²-416x

thus

265+16x²+88x = 400+169x²-416x

16x²-169x²+88x+416x+265-400 = 0

-153x²+504x-135 = 0

we will solve this quadratic equation by suing the quadratic formula to find x

x=(-504±sqrt(504²-4(-153)(-135)))/2(-153)

x=(-504±\sqrt{504^{2}-4(-153)(-135) })/2(-153)

x=(-504±\sqrt{254016-82620 })/-306

x=(-504±\sqrt{171396})/-306

x=(-504±414)/-306

x=(-504+414)/-306 and x=(-504-414)/-306

x=-90/-306 and x=-918/-306

x= 5/17 , 3

substituting x by the roots we found

check for 5/17:

4x+11 = 4×(5/17)+11 = (20/17)+11 = (20+187)/17 = 207/17 ≈ 12.17..

13x-16 = 13×(5/17)-16 = (65/17)-16 = (65-272)/17 = -207/17 ≈ -12.17..

check for 3:

4x+11 = 4×3+11 = 12+11 = 23

13x-16 = 13×3-16 = 23

thus 3 is the right root

therfore

ED=23 and CD=23

FD²=FE²+ED² or FD²=FC²+CD²

FD²=12²+23²

FD²=144+529

FD²=673

FD=√673

FD≈25.94.. rounded = 26

5 0
3 years ago
Read 2 more answers
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