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7nadin3 [17]
3 years ago
13

I need help with this pleas

Mathematics
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer:

What is the question?

Step-by-step explanation:

I cannot see an attachment.

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(3x+18) 4.30 (6x-16)​
Musya8 [376]
What do you need help with?
3 0
2 years ago
Maria sets a goal of jogging 17.5 miles this week she plans on running 2.75 miles each day for seven days if she follows her pla
Anit [1.1K]

Answer:

B

Step-by-step explanation:

So, to figure this out, we must find the total miles Maria ran in a week.

We know that she ran 2.75 miles each day.

She did this for 7 days.

Her goal was 17.5 miles.

So first, multiply the amount of days by the amount of miles per day:

7*2.75

=

19.25

So now we know that she ran a total of 19.25 miles in a week.

Since she onlu needed to run 17.5 miles, we can instantly rule out:

A - Runs less 17.5 miles

C - Runs exactly 17.5 miles

This leaves:

B - She runs 1.75 miles more than 17.5 miles

D - She runs 2.75 miles more than 17.5 miles

To figure out which on is correct, subtract her total miles by her goal:

19.25-17.5

=

1.75

So we know it must be:

B - She runs 1.75 miles more than 17.5 miles

This is because we figured out she ran an extra 1.75 miles.

Hope this helps! :)

6 0
3 years ago
What is the most precise name for quadrilateral ABCD with vertices A(-2, -2), B(-2, 0), C(1, 0), and D(1, -2)
True [87]

D.Trapezoid is the answer

8 0
3 years ago
Read 2 more answers
A farmer has $1500 available to build an E-shaped fence along a straight river so as to create two identical pastures. The mater
Dahasolnce [82]

Answer: The largest dimensions that are possible would be 50 foot by 125 foot.

Step-by-step explanation:

Since we have given that

Amount a farmer has available = $1500

Let x be the side perpendicular to the river.

Let y be the side parallel to the river.

Number of section perpendicular to the river = 3

cost of material for the side parallel to the river = $6 per foot

Cost of material for the side perpendicular to the river = $5 per foot

So, total cost becomes

Cost=6y+5(3x)=1500\\\\Cost=6y+15x=1500\\\\y=\dfrac{1500-15x}{6}}

Area would be

A=x\times y\\\\A=x(\dfrac{1500-15x}{6})\\\\A=\dfrac{1}{6}(1500x-15x^2)\\\\A'=\dfrac{1}{6}(1500-30x)

Now, put A' = 0 to get the critical points.

So, it becomes,

\dfrac{1}{6}(1500-30x)=0\\\\1500-30x=0\\\\1500=30x\\\\x=\dfrac{1500}{30}\\\\x=50

A''=\dfrac{-30}{6}=-5

so, at x= 50 it will give maximum dimensions.

y=\dfrac{1500-15x}{6}=\dfrac{1500-15\times 50}{6}=\dfrac{750}{6}=125

So, the largest dimensions that are possible would be 50 foot by 125 foot.

7 0
3 years ago
Find the measurement of a supplementary angle with 27°
neonofarm [45]

Answer:

153

Step-by-step explanation:

180 - 27 = 153

7 0
3 years ago
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