Question

Please help with problem !!!

Answer 1

Answer:

Step-by-step explanation:

y = 2x^2 - 12x +19                Put brackets around the  1st 2 terms. Take 2

y = 2(x^2 - 6x ) + 19             Take 1/2 of the 6 square it and add inside the brackets

y = 2(x^2 - 6 + (6/2)^2) +19 Subtract 2 *9 from the 19. Express 1st 3 terms as ( )^2

y = 2(x- 3)^2 + 19 - 18

y = 2(x - 3)^2 + 1

Answers

y intercept when x = 0 is y = 19

axis of symmetry x = 3

vertex: (3,1)

Graph

graph: red

axis of symmetry: blue

y intercept, vertex: green