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3 years ago

Solve for x^2=-25 Please help me

Mathematics

2 answers:

Bas_tet [7]3 years ago

4 0

Answer:

Step-by-step explanation:

This is not possible over the real numbers system. You cannot take the square root of a negative number without ending up with imaginary solutions.

$x^2=-25$ and

$x=\sqrt{-25}$ In the world of imaginary numbers, the 2 solutions would be

x = 5i and x = -5i

liq [111]3 years ago

4 0

Answer:

It should be x=5i-5i

Step-by-step explanation:

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A car travels 416 miles in eight hours at that rate how far will the car travel in 22 hours

alisha [4.7K]

Speed = 416 miles / 8hrs = 52 miles per hr.

Distance = Speed * Time = 52 * 22 = 1144miles

7 0

3 years ago

A shoe store uses a 38% markup to price their items. The store buys the

Lorico [155]

Answer:

They will Markup the price by $19.76.

Step-by-step explanation:

Markup percent = 38%

Wholesale Price = $52

Markup price can be calculated by simply multiplying the wholesale price by 38% or 0.38.

Markup price = 38% of 52

= 38/100 × 52

= 0.38 × 52

= $19.76

Therefore, they will Markup the price by $19.76.

8 0

3 years ago

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

Find the value of y

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

Find the values of x

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

4 years ago

JULIE HAS 10 YARDS OF RIBBON. SHE DIVDES THE RIBBON INTO 3 EQUAL PIECES AND USES 2 OF THE PIECES ON GIFTS. HOW MUCH RIBBON DOES

Aliun [14]

Answer:

6.66 yards of ribbon.

Step-by-step explanation:

If she has 10 yards of ribbon and divides it equally into three parts, those 3 parts would each be 3.33 yards long or 3 (1/3) yards long.

If she uses two of those parts on gifts, then she would use 3.33 x 2 or 6.66 yards of ribbon.

8 0

4 years ago

At your job, you are paid $50 per week plus $3 per sale. At least how many sales do you need to make in order to have over $250

julsineya [31]

0+3⋅c>250

50+3⋅c−50>250−50

3⋅c>200

3⋅c3>2003

c>66.7

so 67 sales rouned

6 0

3 years ago