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Eduardwww [97]
2 years ago
13

2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.

Mathematics
1 answer:
shepuryov [24]2 years ago
7 0

Answer:

Step-by-step explanation:

\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\

= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}

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it costs $20 for 4 play tickets and $35 for 7 play tickets. Is cost per ticket constant? why or why not?
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Answer:

The cost per ticket is<u> constant</u>.

Step-by-step explanation:

Given:

It costs $20 for 4 play tickets and $35 for 7 play tickets.

Now, to get whether cost per ticket is constant or not.

So, if the cost per ticket is constant that means the cost of ticket for a play or more is fixed, non-varying and it does not change.

Now, we check it:

4 play tickets costs  = $20.

1 play tickets costs  = $20 ÷ 4 = $5.

So, 7 play tickets costs = $5 × 7 = $35.

Thus, the cost of ticket for play is not changing and it is constant.

So the cost per ticket is constant.

Therefore, the cost per ticket is constant.

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