Answer:
a. positive.
Step-by-step explanation:
Matching and discordant pairs are used to describe the relationship between pairs of observations. To calculate matched and discordant pairs, data is treated as ordinal values. Therefore these are suitable for your application. The number of concordant and discordant pairs is used in Kendall's tau calculations, whose purpose is to determine the relationship among two ordinal variables.
If the direction of the classifications is the same, the pairs are concordant.
A pair of observations is discordant, suppose the subject being with an increased value on one variable is lower on the other.
SO; When discordant pairs exceed concordant pairs in a P-Q relationship, Kendall's tau reports a(n) <u>positive</u> association between the variables under study.
Answer:
Do u know the answer to
Step-by-step explanation:
Triangle ABC is a right triangle. The length of the legs are 3 in and 6 in, how long is the hypotenuse? (Round to the nearest tenth if necessary)
A) 3.3 in
B) 6.7 in
C) 7.9 in
D) 9.0 in
The regular price is 3.18.
50% off half the price, so you can either divide the regular price by 2 or multiply it by 0.50
3.18 / 2 = 1.59 ( 3.18 *0.50 = 1.59)
so the sale price is 1.59
now subtract the sale price from $5 to find the amount of change they got back:
5.00 - 1.59 = $3.14 change back
Step-by-step explanation:
Hi Friend !!!
Here is ur answer !!!
(x-1)(x+1)(x²+1)(x^4 + 1)
= (x²-1)(x²+1)(x^4 + 1)
=( x^4 -1)(x^4 + 1)
=( x^8 -1)
The whole is with the help of (a-b) (a+b) = a²-b²
Hope it helps u :-)
Answer:
It is likely that the birth weight of a random baby boy will be between 3.2 and 3.4 kg because the probability of this event is large enough.
Step-by-step explanation:
Population mean=μ=3.3.
S.E=0.1.
n=36.
If the probability of the birth weight of a random baby boy will be between 3.2 and 3.4 kg is larger than the it will be likely. The probability can be calculated by normal distribution because sample size is large enough.
Z-score for 3.2 kg=3.2-3.3/0.1=-1
Z-score for 3.4 kg=3.4-3.3/0.1=1
P(-1<Z<1)=P(-1<Z<0)+P(0<Z<1)
P(-1<Z<1)=0.3413+0.3413
P(-1<Z<1)=0.6826
The probability of the birth weight of a random baby boy will be between 3.2 and 3.4 kg is 68.26%. So. it is likely that the birth weight of a random baby boy will be between 3.2 and 3.4 kg as the probability is large enough.