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3 years ago

What is the point-slope equation of the line with slope -13 that goes through the point (5, 7)?

1 answer:

7 0

Hello
the point-slope equation of the line with slope -13 that goes through the point (5, 7) is : <span>A) y - 7 = -13(x - 5)
because ; 7-7= -13(5-5)</span>

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How would you write an equation with a slope of 2/3 and a y-intercept of -3

dimaraw [331]

Answer: The answer is C) y= 2/3x-3

Step-by-step explanation:

i figure it out

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3 years ago

Read 2 more answers

What is the volume of the figure below if a = 4.5 units, b = 5.8 units, and c = 3 units?

Anastasy [175]

Answer:

The answer to your question is the letter C

Step-by-step explanation:

Data

a = 4.5 u

b = 5.8 u

c = 3 u

Process

1.- Calculate the volume of the rectangular prisms

Formula

Volume = a x a x c

Substitution

Volume = 4.5 x 4.5 x 3

Result

Volume = 60.75 u³

But there are two rectangular prism

Total volume = 2 x 60.75

= 121.5 u³

2.- Calculate the volume of the triangles

Formula

Volume = base x width x height

Substitution

Volume = 5.8 x 3 x 4.5

Result

Volume = 78.3 u³

3.- Total volume

Volume = 121.5 + 78.3

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3 years ago

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2 years ago

Given f(x)=-1/7√16-x^2 find f^-1(x)

Vera_Pavlovna [14]

Answer:

$f^{-1}(x)=\pm \sqrt{49x^2-16}$

Not a function.

Step-by-step explanation:

The given function is;

$f(x)=-\frac{1}{7}\sqrt{16-x^2}$

Let $y=-\frac{1}{7}\sqrt{16-x^2}$

Interchange x and y;

$x=-\frac{1}{7}\sqrt{16-y^2}$

Solve for y;

$-7x=\sqrt{16-y^2}$

Square both sides

$(-7x)^2=(\sqrt{16-y^2})^2$

$49x^2^2=16-y^2$

$49x^2^2-16=y^2$

$y=\pm \sqrt{49x^2-16}$

The inverse is

$f^{-1}(x)=\pm \sqrt{49x^2-16}$

$f^{-1}(x)=\pm \sqrt{49x^2-16}$ is not a function because one x-value maps onto to different y-values.

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3 years ago

Ronaldo can kick a soccer ball 35 meters per second which is about 80 mph. He kicked the ball from one end of the field to the o

professor190 [17]

Answer:

$t=3.142sec$

Step-by-step explanation:

From the question we are told that:

Speed of ball $V=35m/s\approx 80 mph$

Length of field $l=110m$

Generally the equation for Time taken $t$ is mathematically given by

$t=m/V$

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$t=3.142sec$

$t \approx \frac{3.142}{60}$

$t \approx 0.05hrs$

Therefore it will take the ball to get from one end of the field to the other

$t=3.142sec$

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2 years ago