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WINSTONCH [101]
3 years ago
8

A car at a red light accelerates for 5 seconds and is now travelling 25 m/s. What was the car’s acceleration?

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
5 0

Answer:

5mph

Step-by-step explanation:

zepelin [54]3 years ago
4 0

Answer:

5 m/s²

Step-by-step explanation:

t (time) = 5 s

u (initial velocity) = 0m/s

v (final velocity) = 25m/s

a = (v-u)/t

a = (25-0)/5

a = 25/5

a = 5 m/s²

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\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)}  \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\  \\ \longrightarrow \sf \: 27 - 15 \\  \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}

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