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3 years ago

Please write the answer

Mathematics

1 answer:

Travka [436]3 years ago

6 0

$\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\ \\ \longrightarrow \sf \: 27 - 15 \\ \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}$

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3 years ago

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Answer:

Option D.

Step-by-step explanation:

The formula for total debt ratio is

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It can be rewritten as

$\text{Total debt ratio}=1-\dfrac{\text{Total Equity}}{\text{Total assets}}$ .... (1)

We know that,

$\text{ Equity multiplier}=\dfrac{\text{Total Equity}}{\text{Total assets}}$ ... (2)

Using (1) and (2) we get

$\text{Total debt ratio}=1-\dfrac{1}{\text{Equity multiplier}}$

Substitute total debt ratio=0.46 in the above equation.

$0.46=1-\dfrac{1}{\text{Equity multiplier}}$

$0.46-1=-\dfrac{1}{\text{Equity multiplier}}$

$-0.54=-\dfrac{1}{\text{Equity multiplier}}$

$\text{Equity multiplier}=-\dfrac{1}{-0.54}$

$\text{Equity multiplier}=1.85185185$

$\text{Equity multiplier}\approx 1.85$

Therefore, the correct option is D.

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Using concepts of the inverse function, it is found that:

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<h3>How to find the inverse of an equation or a function?</h3>

To find the inverse, we have to exchange x and y and then isolate y. This can only happen if the function f(x) is injective, that is, each value of the output is related to only one value of the input. Then:

The domain of f(x) is the range of the inverse function f-1(x).

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Researching this problem on the internet, we are given an absolute value function with vertex at x = 1, meaning that for the inverse, the domain of f(x) has to be restricted to x >= 1. The domain of the inverse would be the range of f(x), which is (2,∞).

Then:

The domain of f(x) has to be restricted to x >= 1. Under this restriction, the domain of f-1(x), would be (2,∞), having the same minimum value as the original function f(x).

More can be learned about inverse functions at brainly.com/question/8824268

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2 years ago

Please write the answer​

Please write the answer