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Darya [45]
3 years ago
6

Can someone pls explain what I’m supposed to do I don’t really understand

Mathematics
1 answer:
kirill [66]3 years ago
8 0

Answer:

There are only 3 differences perform

Step-by-step explanation:

I. If x is negative, y is negative then the answer is possitive

            eg. x is -2, y is -3

                  -2 × -3 = 6

II. If x is negative, y is positive then the answer is negative

            eg. x is -1, y is 2

                  -1 × 2 = -2

III. If x is possitive, y is possitive then the answer is positive

             eg. x is 2, y is 5

                    2 × 5 = 10

Alt. No matter how long x, y, z, a, b there always apply only 3 rules above. Multiply or Devide are the same rule.

Ask me for anything :D

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Answer: x = 38.46

Step-by-step explanation:

tan(20) = 14/x

xtan(20) = 14

x = 14/tan(20)

x = 38.46

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24pi inches, or 75.3982237in

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Area = 78.5 ft squared. Find the diameter, and round it to the nearest tenth.​
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A professor has recorded exam grades for 10 students in his​ class, but one of the grades is no longer readable. If the mean sco
Nostrana [21]

Answer:

unreadable score = 35

Step-by-step explanation:

We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".

There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":

1) The mean score of ALL exams (including the unreadable one) is 80

so the equation to represent this statement is:

mean of ALL exams = 80

By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

\frac{R+x}{10} =80

since the mean is the addition of all values divided the total number of exams.

in a similar way we can write what the mean of just the readable exams is:

\frac{R}{9} = 85\\ (notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.

Based on the equation above, we can find what "R" is by multiplying both sides by 9:

\frac{R}{9} = 85\\R=85*9= 765

Therefore we can now use this value of R in the very first equation we created, and solve for "x":

\frac{R+x}{10} =80\\\frac{765+x}{10} =80\\765+x=80*10=800\\765+x=800\\x=800-765=35

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