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MakcuM [25]
2 years ago
5

What is 3/8 of 200? pls show work 35 POINTS!!!

Mathematics
1 answer:
yanalaym [24]2 years ago
3 0

Answer:

The answer is 75

Step-by-step explanation:

3/8*200=75.

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336

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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
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The following table shows the salary of 7 people in an office last year.
kotegsom [21]

Answer:

a.  £24,714.29

b. £16,833.33

Step-by-step explanation:

The calculation of mean income is given below:-

Mean income = Total addition of salaries ÷ Number of workers

= £9,500 + £25,000 + £13,250 + £72,000 + £12,750 + £29,500 + £11,000

= £173,000 ÷ 7

= £24,714.29

Now,

the Mean income excluding Deva's salary:

= Formula of Mean income

= Total addition of salaries excluding Deva salary ÷ Number of workers

= (£9,500 + £25,000 + £13,250 + £12,750 + £29,500 + £11,000) ÷ 6

= £101,000 ÷ 6

= £16,833.33

7 0
3 years ago
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