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Andreas93 [3]
2 years ago
8

On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (negative 2, 3) an

d (0, negative 1). Everything to the left of the line is shaded. The second dashed line has a negative slope and goes through (0, 2) and (1, 0). Everything to the right of the line is shaded.
Which inequality pairs with y≤−2x−1 to complete the system of linear inequalities represented by the graph?

y<−2x+2
y>−2x+2
y<2x−2
y>2x−2
Mathematics
1 answer:
alina1380 [7]2 years ago
5 0

Answer:

y > -2x + 2

Step-by-step explanation:

The dashed line tells us the answer doesNOT have the "or=to" under the inequality symbol. Then the y-intercept is positive 2. So it must be

y > -2x + 2

see image

Look at the y-intercept and think of up/down instead of left/right on the shading and then you can see whether its < or >

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determine the value of x for which r parallels s. then find the measure of angle 1 and the measure of angle 2measure angle 1= 50
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According to the picture, angles 1 and 2 have the same measure because they are corresponding angles. Make equal both expressions for 1 and 2 and find x.

\begin{gathered} 50-2x=110-42x \\ 42x-2x=110-50 \\ 40x=60 \\ x=\frac{60}{40} \\ x=\frac{3}{2} \end{gathered}

x is 3/2. Replace this value in both expression to find the measure of each angle.

\begin{gathered} \measuredangle1=50-2x \\ \measuredangle1=50-2(\frac{3}{2}) \\ \measuredangle1=50-3 \\ \measuredangle1=47 \\ \measuredangle2=110-42x \\ \measuredangle2=110-42(\frac{3}{2}) \\ \measuredangle2=110-63 \\ \measuredangle2=47 \end{gathered}

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