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3 years ago

Evaluate the exponent expression for a = –2 and b = 3.

Mathematics

2 answers:

Gnom [1K]3 years ago

7 0

Answer:

- 9/8

Step-by-step explanation:

-2a^-3b^2/a where a = -2 and b = 3

-2(-2)^-3(3)^2/(-2)

-2(- 1/8)(9)/(-2)

-2(- 9/8)/(-2)

9/4/(-2) or…

2.25/(-2)

-1.125 or - 9/8

serious [3.7K]3 years ago

6 0

Answer:

The choose B) -9/8

Step-by-step explanation:

$\frac{ - 2a ^{ - 3 } {b}^{2} }{a} \\ \frac{ - 2( - 2)^{ - 3} {3}^{2} }{ - 2} \\ \frac{ - 2(9)}{ - 2( - 8)} = - \frac{9}{8}$

I hope I helped you^_^

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185g shared to the ratio of 2:3

Yuliya22 [10]

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3 years ago

7 over 12 minus 5 over 12 as a fraction in simplest form

poizon [28]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

If you choose two cards at random from a deck of 52 cards, what is the probability that it is two diamonds?

kari74 [83]

<h3>Answer:</h3>

1/17 or 0.0588 (without replacement)

<h3>Step-by-step explanation:</h3>

To answer this question we need to know the following about a deck of cards

A deck of cards contains 4 of each card (4 Aces, 4 Kings, 4 Queens, etc.)
Also there are 4 suits (Clubs, Hearts, Diamonds, and Spades).
Additionally, there are 13 cards in each suit (Clubs/Spades are black, Hearts/Diamonds are red) .

In this case, we are required to determine the probability of choosing two diamonds.

There are 13 diamonds in the deck.
Assuming, the cards were chosen without replacement;

P(Both cards are diamonds) = P(first card is diamond) × P(second card is diamond)

P(First card is diamond) = 13/52

If there was no replacement, then after picking the first diamond card, there are 12 diamond cards remaining and a total of 51 cards remaining in the deck.

Therefore;

P(Second card is diamond) = 12/51

Thus;

P(Both cards are diamonds) = 13/52 × 12/51

= 156/2652

= 1/17 or 0.0588

Hence, the probability of choosing two diamonds at random (without replacement) is 1/17 or 0.0588.

5 0

4 years ago

Tim has to cover 3 tanks completley with paint.

bija089 [108]

answer:

<h3>Total surface area of 3 tanks=34.3 m^2</h3><h3>7 tins of paint are required.</h3>

Solution,

diameter of tank=1.4 m

Height of tank=1.9 m

Given tank has top and bottom 

Now, The total surface area of cylinder tank is given by:

 $tsa = 2\pi \: {r}^{2} + (2\pi \: r \: ) \times h$ 

r( radius of tank)=

 $\frac{diameter}{2} = \frac{1.4}{2} = 0.7 \: m$ 

h(height of tank)=1.9 m

TSA of 1 tank

=

 $2 \times 3.14 \times {(0.7)}^{2} + 2 \times 3.14 \times 0.7 \times 1.9 \\ = 11.435 \: {m}^{2}$ 

TSA Of 3 tanks

=

 $3 \times 11.435 \: {m}^{2} \\ = 34.3 \: {m}^{2}$ 

Given a tin of plate covers 5m^2 area.

No.of tins required:

1 tin 5m^2

x tin 34.3 m^2

 $5x = 34.3(cross \: multiplication) \\ or \: x = \frac{34.3}{5} \\ x = 6.86 \\ x = 7 \: tins$ 

therefore 7 tins are required.

Hope this helps...

Good luck on your assignment....

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3 years ago

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alexira [117]

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