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Rufina [12.5K]
2 years ago
13

Tim has to cover 3 tanks completley with paint. ​

Mathematics
1 answer:
bija089 [108]2 years ago
8 0

<em>answer:</em>

<h3><em>Total </em><em>surface </em><em>area </em><em>of </em><em>3</em><em> </em><em>tanks=</em><em>3</em><em>4</em><em>.</em><em>3</em><em> </em><em>m^</em><em>2</em></h3><h3><em>7</em><em> </em><em>tins </em><em>of </em><em>paint </em><em>are </em><em>required</em><em>.</em></h3>

<em>Solution</em><em>,</em>

<em>diameter </em><em>of </em><em>tank=</em><em>1</em><em>.</em><em>4</em><em> </em><em>m</em>

<em>Height </em><em>of </em><em>tank=</em><em>1</em><em>.</em><em>9</em><em> </em><em>m</em>

<em>Given </em><em>tank </em><em>has </em><em>top </em><em>and </em><em>bottom </em>

<em>Now,</em><em> </em><em>The </em><em>total </em><em>surface </em><em>area </em><em>of </em><em>cylinder </em><em>tank </em><em>is </em><em>given </em><em>by:</em>

<em>tsa = 2\pi \:  {r}^{2}  + (2\pi \: r \: ) \times h</em>

<em>r(</em><em> </em><em>radius </em><em>of </em><em>tank)</em><em>=</em>

<em>\frac{diameter}{2}  =  \frac{1.4}{2}  = 0.7 \: m</em>

<em>h(</em><em>height </em><em>of </em><em>tank)</em><em>=</em><em>1</em><em>.</em><em>9</em><em> </em><em>m</em>

<em>TSA </em><em>of </em><em>1</em><em> </em><em>tank</em>

<em>=</em>

<em>2 \times 3.14 \times  {(0.7)}^{2}  + 2 \times 3.14 \times 0.7 \times 1.9 \\  = 11.435 \:  {m}^{2}</em>

<em>TSA </em><em>Of </em><em>3</em><em> </em><em>tanks</em>

<em>=</em>

<em>3 \times 11.435 \:  {m}^{2}  \\  = 34.3 \:  {m}^{2}</em>

<em>Given </em><em>a </em><em>tin </em><em>of </em><em>plate </em><em>covers </em><em>5</em><em>m</em><em>^</em><em>2</em><em> </em><em>area.</em>

<em>No.of </em><em>tins </em><em>required:</em>

<em>1</em><em> </em><em>tin</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>5</em><em>m</em><em>^</em><em>2</em>

<em>x </em><em>tin</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em><em>4</em><em>.</em><em>3</em><em> </em><em>m^</em><em>2</em>

<em>5x = 34.3(cross \: multiplication) \\ or \: x =  \frac{34.3}{5}  \\ x = 6.86 \\ x = 7 \: tins</em>

<em>there</em><em>fore</em><em> </em><em>7</em><em> </em><em>tins </em><em>are </em><em>required</em><em>.</em>

<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>

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