Find the measure of angle of ABF
1 answer:
Answer: m∠ABF = 120°
Concept:
Here, we need to know the idea of the <u>corresponding angle theorem </u>and <u>linear pair postulate</u>.
The corresponding angle theorem states that if a transversal cuts two parallel lines, their corresponding angles are congruent.
The linear pair postulate states that two angles that form a linear pair are supplementary.
Solve:
<u>Given information</u>
m∠ABF = m∠ABF = 2x + 3x
- According to the corresponding angle theorem, ∠ABF is congruent to ∠BCI which is 2x + 4x.
m∠BCH = 3x
Total angle = 180°
- ∠ABF and ∠BCH are linear pairs which means they form a supplementary angle.
<u>Given equation</u>
m∠ABF + m∠BCH = Total Angle
<u>Substitute values into the equation</u>
2x + 4x + 3x = 180
<u />
<u>Combine like terms</u>
9x = 180
<u>Divide 9 on both sides</u>
9x / 9 = 180 / 9
x = 20
m∠ABF = 2x + 4x = 2 (20) + 4 (20) = 40 + 80 = <u>120°</u>
Hope this helps!! :)
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Answer:
<em>The answer is</em> <em>{-(5)
(36)×
-(180)</em>
Step-by-step explanation:
A polynomial with rational coefficients has roots 5 and -6i (There i is the
imaginary number not variable )
As we knew that imaginary no comes in pair . This means that if -6i is
one root then the other root will be 6i
So if we assume the lowest polynomial that is possible is given as
{-(sum of all roots)
+(roots taken two at a time)
-(product of all roots)
{-(5+6i+(-6i))
+(5×6i +5×(-6i) +6i×(-6i))
-(5×6i×(-6i))
= -1
<em>{-(5)
(36)×
-(180)</em>
<em> </em>The <u>general case</u> we assume that the three previous roots and rest roots
a4,a5,a6 ...............an
-(sum of all roots)×
+(roots taken two at a
time) ×- .......................................... (product of all roots)