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11111nata11111 [884]
3 years ago
13

Which direction do electrons travel

Physics
1 answer:
Sedaia [141]3 years ago
5 0

Answer:

option a negative to positive

Explanation:

The flow of electrons is termed electron current. Electrons flow from the negative terminal to the positive. Conventional current or simply current, behaves as if positive charge carriers cause current flow. Conventional current flows from the positive terminal to the negative

brainliest plsss

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The first law of thermodynamics states that heat added to a system is neither created nor destroyed but is _______________
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Answer:

Transferred

Explanation:

It only changes from one state to another

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Where in the world does average daily temperature exceed the annual temperature range?
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The average daily annual temperature range is exceeded in places such as deserts. Deserts tend to be hotter due to the lack of water contained within them. This means that all of the sun's thermal radiation heats up the ground and air. These factors cause deserts to have above average temperatures.
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The first charged object is exerting a force on the second charged object. Is the second charged object necessarily exerting a f
mario62 [17]

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Explanation:

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HAPPY LEARNING:)

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3 years ago
7. A double-slit experiment uses coherent light of wavelength 633 nm with a slit separation of 0.100 mm and a screen placed 2.0
Illusion [34]

Answer:

The distance between first-order and second-order bright fringes is 12.66mm.

Explanation:

The physicist Thomas Young establishes through its double slit experiment a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.

\Lambda x = L\frac{\lambda}{d}  (1)

Where \Lambda x is the distance between two adjacent maxima, L is the distance of the screen from the slits, \lambda is the wavelength and d is the separation between the slits.  

The values for this particular case are:

L = 2.0m

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Notice that is necessary to express L and \lambda in units of milimeters.

L = 2.0m \cdot \frac{1000mm}{1m} ⇒ 2000mm

\lambda = 633nm \cdot \frac{1mm}{1x10^{6}nm} ⇒ 6.33x10^{-4}mm

Finally, equation 1 can be used:

\Lambda x = (2000mm)\frac{(6.33x10^{-4}mm)}{(0.100mm)}

\Lambda x = 12.66mm

Hence, the distance between first-order and second-order bright fringes is 12.66mm.

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3 years ago
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Hope that helps :)

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3 years ago
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