Ask question

Ask question

All categories

2 years ago

15

The first charged object is exerting a force on the second charged object. Is the second charged object necessarily exerting a f

orcer on the first?

1 answer:

mario62 [17]2 years ago

6 0

Answer:

Explanation:

Of course because it's Newton's Law that if body A exerts force on body B, then body B will exert equal but opposite force on body A.

HAPPY LEARNING:)

You might be interested in

Anna pushes a box with a force of 8.00 newtons. She generates a power of 3.00 watts. How much time does it take for Anna to move

QveST [7]

Power is the energy in a system per time. It will have units of Watts which is equal to joules per second. It can be expressed as:

P = E / t

where E = Force x distance

P = Fd / t
t = Fd / P
t = 8 (9.72) / 3.0
t = 25.92 s

8 0

3 years ago

Read 2 more answers

When light of wavelength 240 nm falls on a cobalt surface, electrons having a maximum kinetic energy of 0.17 eV are emitted. Fin

dusya [7]

Answer:

(a) 5.04 eV (B) 248.14 nm (c) $1.21\times 10^{15}Hz$

Explanation:

We have given Wavelength of the light \lambda = 240 nm

According to plank's rule ,energy of light

$E = h\nu = \frac{hc}{}\lambda$

$E = h\nu = \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{ 240\times 10^{-9} m\times 1.6\times 10^{-19}J/eV}= 5.21 eV$

Maximum KE of emitted electron i= 0.17 eV

Part( A) Using Einstien's equation

$E = KE_{max}+\Phi _{0}$ , here $\Phi _0$ is work function.

$\Phi _{0}=E - KE_{max}$ = 5.21 eV-0.17 eV = 5.04 eV

Part( B) We have to find cutoff wavelength

$\Phi _{0} = \frac{hc}{\lambda_{cuttoff}}$

$\lambda_{cuttoff}= \frac{hc}{\Phi _{0} }$

$\lambda_{cuttoff}= \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{5.04 eV\times 1.6\times 10^{-19}J/eV }=248.14 nm$

Part (C) In this part we have to find the cutoff frequency

$\nu = \frac{c}{\lambda_{cuttoff}}= \frac{3\times 10^{8}m/s}{248.14 \times 10^{-19} m }= 1.21\times 10^{15} Hz$

5 0

3 years ago

All are examples of electric forces except _________. A. a neutron pushing on another neutron B. an electron pushing on a proton

Contact [7]

Answer:

A) a neutron pushing on another neutron.

Explanation:

Neutrons have no charge, therefore, there is no electric force among them. Protons and electrons on the other hand do have electric charge (electrons negative charge and protons positive charge) that generate electric forces between them that can be repelling forces (if the charges are of the same sign), or attractive forces (if the charges are of opposite signs).

6 0

3 years ago

A 12.0 kg rock slides off the edge of a bridge and falls into the water 25.0 meters below. what is the kinetic energy of the roc

Pavel [41]

During the fall, all the initial potential energy of the rock
$U=mgh$
has converted into kinetic energy of motion
$K= \frac{1}{2}mv^2$
where h is the initial height of the rock, m its mass, and v its velocity just before hitting the water. So, for energy conservation, we have
$U=K$
and so we can find the value of K, the kinetic energy of the rock just before hitting the ground:
$K=U=mgh = (12.0 kg)(9.81 m/s^2)(25.0 m)=2943 J$

7 0

3 years ago

Please help me look at the image below

djverab [1.8K]

I can’t see anything

7 0

2 years ago