Answer:
Vo = 4.5 [m/s]
Explanation:
In order to solve this problem, we must use the following equation of kinematics.

where:
Vf = final velocity = 12 [m/s]
Vo = initial velocity [m/s]
a = acceleration = 1.5 [m/s²]
t = time = 5 [s]
Now replacing:
![12=v_{o}+1.5*5\\v_{o}=12- (7.5)\\v_{o}= 4.5[m/s]](https://tex.z-dn.net/?f=12%3Dv_%7Bo%7D%2B1.5%2A5%5C%5Cv_%7Bo%7D%3D12-%20%287.5%29%5C%5Cv_%7Bo%7D%3D%204.5%5Bm%2Fs%5D)
Answer:
the velocity of car when it passes the truck is u = 16.33 m/s
Explanation:
given,
constant speed of truck = 28 m/s
acceleration of car = 1.2 m/s²
passes the truck in 545 m
speed of the car when it just pass the truck = ?
time taken by the truck to travel 545 m
time =
time =
time =19.46 s
velocity of the car when it crosses the truck


u = 16.33 m/s
the velocity of car when it passes the truck is u = 16.33 m/s