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Rashid [163]
3 years ago
5

Answer all of these for 100 points

Mathematics
1 answer:
KiRa [710]3 years ago
8 0

Answer:

Step-by-step explanation:

37) Take two point from the line.

(2 , 0)  & (0,4)

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{4-0}{0-2}\\\\=\frac{4}{-2}\\\\=-2

Slope = (-2)

38)  (7 , 0) & (3 , 2)

Slope = \frac{2-0}{3-7}\\\\=\frac{2}{-4}\\\\=\frac{-1}{2}

39) The line is parallel to x-axis and so its slope is 0

Slope = 0

40) The line is parallel to y-axis and so its slope is undefined

Slope = undefined

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A school bus is moving 26.8 m/s on flat ground when it begins to accelerate at 4.73 m/s^2. How much time does it take to travel
leva [86]

The school bus will take 5.34 seconds to travel 95.1 m if the bus is moving 26.8 m/s on flat ground when it begins to accelerate at 4.73 m/s².

<h3>What is a quadratic equation?</h3>

Any equation of the form \rm ax^2+bx+c=0 where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}

We have:

A school bus is moving 26.8 m/s on flat ground when it begins to accelerate at 4.73 m/s².

From the second equation of motion:

\rm s = u + \dfrac{1}{2}at^2

We have given:

s = 95.1 m

u = 26.8 m/s

a = 4.73 m/s²

\rm 95.1 = 26.8 + \dfrac{1}{2}(4.73)t^2

The above equation is a quadratic equation:

After simplification:

\rm \dfrac{4.73}{2}t^2=68.3

\rm t^2=28.879

t = 5.373 seconds ≈ 5.34 seconds

Thus, the school bus will take 5.34 seconds to travel 95.1 m if the bus is moving 26.8 m/s on flat ground when it begins to accelerate at 4.73 m/s².

Learn more about quadratic equations here:

brainly.com/question/2263981

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