Use the table to answer the question. Note: Round z-scores to the nearest hundredth and then find the required A values using th
e table. A manufacturer of light bulbs finds that one light bulb model has a mean life span of 1025 h with a standard deviation of 88 h. What percent of these light bulbs will last as follows? (Round your answers to one decimal place.) (a) at least 940 h
(b) between 850 and 900 h 
(b) between 850 and 900 h
1 answer:
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Answer:
The parents who didn't answer with either naughty and nice are <u>6</u>.
Step-by-step explanation:
Given:
150 parents were surveyed. 26% said that the kids were naughty and 70% said their kids were nice.
Now, to find parents who didn't answer with either naughty and nice.
<em>So, as given in question:</em>
<em>70% said that their kids are naughty.</em>
<em>26% said that their kids are nice.</em>
So, to get the percentage of parents who didn't answer we subtract.
<em>Thus, the percentage of parents who didn't answer with either naughty and nice:</em>
100% - (70% + 26%)
100% - 96% = 4%.
Hence, 4% of parents didn't answer.
Now, to get how many parents didn't answer we calculate the percentage of the total who didn't answer:
<em>Total parents surveyed = 150.</em>
<em>Parents who didn't answer = 4% of the total parents surveyed.</em>
Therefore, the parents who didn't answer with either naughty and nice are 6.