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GREYUIT [131]
2 years ago
9

Find f(g(4)) if f(x)=2x+1 and g(x)=x^2

Mathematics
2 answers:
Gala2k [10]2 years ago
6 0

Answer:

is this even math????

Step-by-step explanation:

Vikki [24]2 years ago
5 0

First solve g(x) by replacing x with 4

G(x) = x^2 = 4^2 = 16

Now replace x in f(x) with 16:

F(x) = 2x + 1 = 2(16) + 1 = 32 +1 = 33

The answer is 33

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Answer: the first one

Step-by-step explanation: head math

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3 years ago
Stephanie has pennies, nickels, dimes, and quarters in her piggy bank. The total value of the coins is 0.01(n + 10) + 0.05n + 0.
stepladder [879]

Answer:

A. the number of pennies

Step-by-step explanation:

.01 is the numerical value of a penny

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2 years ago
In a survey of 155 senior​ executives, 51​% said that the most common job interview mistake is to have little or no knowledge of
madam [21]

Answer:

B

Step-by-step explanation:

8 0
2 years ago
A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the
grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = \frac{diameter}{2}=\frac{66}{2} =33 \ mm

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = \frac{4}{3}\pi r^3

Now Volume of Gumball = \frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = \frac{diameter}{2}=\frac{58}{2} =29 \ mm

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = \frac{4}{3}\pi r^3

So Volume of gumball's spherical hollow core = \frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = 150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = 48347.6\ mm^3

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0
2 years ago
a parallelogram has a base of 3 feet and a height of 5 feet. The base and height will each be doubled. Will the area also be dou
navik [9.2K]

Answer:

No, doubling the base and height would actually quadruple the area,

Step-by-step explanation:

With the original measurements of b = 3 ft and h = 5 ft,

<em>b x h = A</em>

<em>(3) x (5) = </em><em>15 ft</em>

So lets say we <em>doubled</em> the factors:

<em>(2)(3) x (2)(5) = A</em>

We would end up with 60 feet, four times that of 15.

<em>(6) x (10) = </em><em>60 ft</em>

3 0
3 years ago
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