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Furkat [3]
3 years ago
12

How does translation affect the properties of a two-dimensional figure? please i need help

Mathematics
1 answer:
LiRa [457]3 years ago
7 0

Answer:

It affects the location of the shape and how the shape looks. It doesn't affect the area or perimeter though.

Step-by-step explanation:

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(y+3):(y+5)=k:1<br><br> show that y=(5k-3)/(1-k)<br><br> hence y=(5k-2)/(1-k)
luda_lava [24]

hi,

Express the ratios in fractional form, that is

= ( cross- multiply )

y + 3 = k(y + 5) ← distribute

y + 3 = ky + 5k ( subtract ky from both sides )

y - ky + 3 = 5k ( subtract 3 from both sides )

y - ky = 5k - 3 ← factor out y from each term on the left side

y(1 - k) = 5k - 3 ← divide both sides by (1 - k)

y = 5k- 3

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1 - k

4 0
3 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Which of the following are solutions to x-1 = 5x + 2 ? Check all that apply.
Ad libitum [116K]

Answer:

The answer is-3/4

Step-by-step explanation:

#Hope it helps uh.....

5 0
3 years ago
-2 1/2 * (1 2/3) = what?
TiliK225 [7]

Answer:

4.16

Step-by-step explanation:

Mixed Number = 4 1/6

Decimal = 4.16

Fraction = 4.1666666

Percentage = 416%

7 0
3 years ago
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Mike runs cross country. He runs 7 miles in 56
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It will take him 120 mins as he runs 8 minute miles
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3 years ago
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