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3 years ago

Need help explaining why this happens

Mathematics

1 answer:

Charra [1.4K]3 years ago

8 0

Just like 2 squared = 4, the square root of 2 multiplied by itself will result in a product of 2. Squaring a number always means multiplying that number by the same number.

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Tom and Jerry's Pizza Parlor changes $8.00 for large cheese pizza. Each additional topping is $1.

Scorpion4ik [409]

Answer:

Step-by-step explanation:

The price per pizza is $8.00 with additional toppings priced at $1.00 each.

If x represents the number of additional toppings, then the prizza price is

p(x) = $8.00 = ($1.00/topping)x, where 0 ≤ x < ∞

4 0

3 years ago

40 POINTS FOR THIS (HELP)(Bad at algebra) - In two or more complete sentences, compare the number of x-intercepts in the graph o

DochEvi [55]

Your second equation has 2 x-intercepts because its curve goes beneath the x-axis, meaning it crosses the x-axis twice. Your first equation has only one x intercept because its vertex touches the x-axis. The transformation that occurred was a vertical shift downwards, (since the image function has that little -7 at the end : ) )

4 0

2 years ago

13. A high school has 1600 students. In a random sample of 50 students, 15

Orlov [11]

Answer:

480

Step-by-step explanation:

In 50 student's play station is owned by =15 student's

∴ In 1 student play station is owned by =15÷50 student

∴In 1600 student's play station is owned by =(1600×15)÷50 student's

=480 student's

∴The number of the student at the high school who

own a Play station is 480

(Ans)

3 0

3 years ago

Can you please help me

svetlana [45]

Answer:

∠TUV = 56°

Step-by-step explanation:

∠TUV = 1/2 ∠TWV

∠TUV = 112° ÷ 2 = 56°

7 0

3 years ago

Read 2 more answers

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

2 years ago