Answer:
q=7.7
Step-by-step explanation: This is trigonometry and you would use cosine since you have H (29) as your known and A (q) as your unknown. You would do cos(39)29=7.7
Step-by-step explanation:
here
10^2=8^2+X^2
X^2=100-64
X=√36
X=6
To get the z-value of the scores of the four students, we are going to use the formula for standard score or z-score. It is score minus the mean score, then divided by standard deviation.
z= Score (X)-Mean / SD
To find the z-value of each score, we have to use a Z table. Using the z-score, we are to look first at the y-axis of the table which will highlight the first two digits of the z-score. Then, the x-axis for the second decimal place of the z-score.
You can use this as reference for the z-table: http://www.stat.ufl.edu/~athienit/Tables/Ztable.pdf
Mean= 500SD= 100Scores= 560, 450, 640, 530
For the student who scored 560,z= X-Mean / SDz= 560-500 / 100z= 60 / 100z= 0.6
The score is 0.6 standard deviation above the mean. The z-value is 0.7257 or 72.57%.
For the student who scored 450,z= X-Mean / SDz= 450-500 / 100z= -50 / 100z= -0.5
The score is -0.5 standard deviation above the mean. The z-value is 0.3085 or 30.85%.
For the student who scored 640,z= X-Mean / SDz= 640-500 / 100z= 140 / 100z= 1.4
The score is 1.4 standard deviation above the mean. The z-value is 0.9192 or 91.92%.
For the student who scored 530,z= X-Mean / SDz= 530-500 / 100z= 30 / 100z= 0.3
The score is 0.3 standard deviation above the mean. The z-value is 0.6179 or 61.79%.
Answer:
The money was invested for 8 years.
Step-by-step explanation:
Given that a principal of $ 20,000 is invested at 6.25% and earns $ 10,000 simple interest, to determine how many years has the money been invested, the following calculation has to be performed:
(20,000 x 0.0625) x X = 10,000
1,250X = 10,000
X = 10,000 / 1,250
X = 8
Thus, the money was invested for 8 years.
60% more than regular size. 230.4.
