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vladimir1956 [14]
3 years ago
7

Given a dilation around the origin, what is the scale factor K? D o, K = (2,4) → (3,6)

Mathematics
1 answer:
fenix001 [56]3 years ago
5 0

Answer: 3/2

Step-by-step explanation:

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What is the quotient written in scientific notation? 6 x 10^24 /8 x 10^8
Artist 52 [7]

When you divide 6x10^24 by 8x10^8 you end up with \frac{6}{8} x10^{16}

This simplifies to 0.75x10^{16}

Now this number is not written in scientific notation as it does not have its first digit before the decimal, so we must move the decimal of this one to the right.

To do that you must multiply the number by 10.

This means that the exponet of 10 must decrease by 1.

This makes the answer 7.5x10^{15}

6 0
3 years ago
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What is the coefficient of 43k?
OLEGan [10]
43.
The coefficient of something is the numerical value in that term. For example, if we have 4x. The coefficient is 4.
4 0
3 years ago
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Given f(x) = √(x-3) , what is the positive value of f(12)?
Shalnov [3]

Answer:

3

Step-by-step explanation:

Given

f(x) = \sqrt{(x-3)} , then

f(12) = \sqrt{12-3} = \sqrt{9} = ± 3

There are 2 values 3 and - 3

The positive value of f(12) is + 3

6 0
3 years ago
Can someone help me solve for x please it’s urgent
Lina20 [59]

Answer:

37.5

Step-by-step explanation:

16/46 = 20/(20+x)

or, 16(20+x) = 46×20

or, 320 + 16x = 920

or, 16x = 600

or, x = 600/16

x = 37.5

6 0
3 years ago
6. Find an exact value. (1 point)
vladimir2022 [97]
<span>6 Find an exact value. 
sin 75°
</span>sin(A+B)=sin(A)cos(B)+cos(A)sin<span>(B)
</span>sin(45)=cos(45)=(2^0.5)/2    sin(30)=0.5      cos(30)=(3^0.5)/2
sin(45+30)=sin(45)cos(30)+cos(45)sin(30)=(6^0.5+2^0.5)/4
the answer is the letter d) quantity square root of six plus square root of two divided by four.

<span>7. Find an exact value. 
sine of negative eleven pi divided by twelve.

</span>sin(-11pi/12) = -sin(11pi/12) = -sin(pi - pi/12) = -sin(pi/12) = -sin( (pi/6) / 2)

= - sqrt( (1-cos(pi/6) ) / 2) = -sqrt( (1-√3/2) / 2 ) = -(√3-1) / 2√2=(√2-√6)/4
the answer is the letter c) quantity square root of two minus square root of six divided by four.

<span>8. Write the expression as the sine, cosine, or tangent of an angle. 
sin 9x cos x - cos 9x sin x
</span>

sin(A−B)=sinAcosB−cosAsinB

sin(9x−x)= sin9xcosx−cos9xsinx= sin(8x)

the answer is the letter c) sin 8x

<span>9. Write the expression as the sine, cosine, or tangent of an angle. 
cos 112° cos 45° + sin 112° sin 45°

</span>

cos(A−B)=cosAcosB<span>+sinA</span>sinB

cos(112−45)=cos112cos45<span>+sin112</span>sin45=cos(67)

the answer is the letter d) cos 67°

10. Rewrite with only sin x and cos x.

sin 2x - cos 2x

 

sin2x = 2sinxcosx<span>
cos2x = (cosx)^2 - (sinx)^2 = 2(cosx)^2 -1 = 1- 2(sinx)^2</span>

sin2x- cos2x=2sinxcosx-(1- 2(sinx)^2=2sinxcosx-1+2(sinx)^2

sin2x- cos2x=2sinxcosx-1+2(sinx)^2

<span>the answer is the letter <span>b) 2 sin x cos2x - 1 + 2 sin2x</span></span>
4 0
3 years ago
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