What digit placed in the blank would make the number 138_ divisible by both 4 and 5

Mathematics

2 answers:

kap26 [50]3 years ago

7 0

Answer:

The digit that should be placed in the blank is 0.

Step-by-step explanation:

We are given the four-digit number: 138_

And we want to determine the digit that should be placed in the blank to make the number be divisible by both 4 and 5.

A number that is divisible by 5 must end in either 0 or 5. This leaves us with only two options: 1380 or 1385.

Recalling divisibility rules, for a number to be divisible by 4, its last two digits must be divisible by 4.

80 is indeed divisible by 4, while 85 is not.

In conclusion, the digit that should be placed in the blank is 0, with the number being 1380.

MrRissso [65]3 years ago

7 0

Just to get points……

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Note: Your system of equations is missing some details. Since the procedure is same so it should not be matter as it would still make your understand the concept. So I am assuming you have the following system of equations:

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The two lines intersect at (3/31, 47/31) which is the solution to this system of equations.

The graph of the solution is also attached below.

Step-by-step explanation:

Given the system of the equations

$20x\:+\:4y\:=\:8$

$-21x+\:2y\:=\:1$

The solution will be the point of intersection of two lines. So we need to solve the system of the equations to find the point of intersection in order to graph the solution.

Solving

$\begin{bmatrix}20x+4y=8\\ -21x+2y=1\end{bmatrix}$