The equation of the line containing the points (20,28) and (25,38) is
y = 2x ₋ 12.
Given the points are: (20,28) and (25,38)
First find the slope of the line passing through the given points.
we know that (x₁,y₁) and (x₂,y₂) is m = y₂ ₋ y₁/x₂ ₋ x₁
therefore the slope of line passing through the points (20,28) and (25,38) is:
m = 38 ₋ 28/25 ₋ 20
m = 10/5
m = 2
Consequently, the line's slope is 2.
Find the y-intercept now by using the slope and one of the two points.
y = mx ₊ b
28 = 2(20) ₊ b
28 = 40 ₊ b
28 ₋ 40 = b
b = ₋12
Next, represent the equation in slope-intercept form as follows:
y = mx ₊ b
y = 2x ₋ 12
hence the equation of the line is y = 2x ₋ 12.
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