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GarryVolchara [31]
4 years ago
11

Solving and graphing linear equations practice Y=x+2

Mathematics
1 answer:
grin007 [14]4 years ago
4 0
X=2
Y=4
There are more than 1 solution
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35 POINTS!!!<br>Questions 14-20 please help!
mr_godi [17]
14. sometimes, you can have a 45-45-90 or 60-30-90 triangle (degrees)
sometimes true
15. always
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3 years ago
Plsss help!!!!!!!!!!!
olga55 [171]
You’re correct, it’s the first option
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4 years ago
A)<br> 4x - 3 = 2x + 7<br> -<br> |<br> 4
valina [46]

Answer:

x = 5

Step-by-step explanation:

4x - 3 = 2x + 7

4x - 2x = 7 + 3

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x = 10/2

8 0
3 years ago
A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air​ resistance, its heigh
lara [203]
This problem involves the use of a kinematic equation since it involves the motion of an object. The equation for the height of the object is given as:

s = -<span>16*t^2+v_o*t

Also, the initial velocity, v_o, was also said to be equal to 128 ft/s.

For the first question, </span><span>the​ time(s) that the projectile will reach a height of 240 ft when v_o is 128 feet per second, can be solved using the given equation and the quadratic formula. The resulting quadratic equation is then </span>-16*t^2 + 128*t -240 =0, where a =16, b =128, and c =-240. The quadratic formula is equal to [-b <span>± sqrt(b^2 -4ac)]/2a. This gives two answers t = 3 seconds and t = 5 seconds. This might be because the projectile has a parabolic path, thus, it reaches the height of 240 ft, before and after it reaches a peak.

For the second question, the time it takes for the projectile to reach the ground is obtained by setting the distance, s, equal to zero. In this case, t = 8 seconds.</span>
5 0
3 years ago
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