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3 years ago

Solving and graphing linear equations practice Y=x+2

Mathematics

1 answer:

grin007 [14]3 years ago

4 0

X=2
Y=4
There are more than 1 solution

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Given the diagram below, which of the following statements is NOT true? The image is of two lines SQ and PR intersecting at poin

Nookie1986 [14]

Answer:

Step-by-step explanation:

4 0

3 years ago

Your plan was to be on the road by 9 A.M. but you did not leave the garage until 10 A.M. You then drove with the cruise control

Wittaler [7]

Answer:

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

Step-by-step explanation:

The average speed is given by the following equation:

$v = \frac{d}{t}$

From 10A.M. to noon.

You traveled at 50mph during 2 hours. So how long you traveled?

$50 = \frac{d}{2}$

$d = 50*2$

$d = 100$

You traveled 100 miles.

What was your average speed over the time interval from 9 A.M. to noon

From 9 A.M. to 10 A.M, you did not travel.

From 10 P.M. to noon, 100 miles.

So 100 miles during 3 hours.

$v = \frac{d}{t} = \frac{100}{3} = 33.33$

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

8 0

2 years ago

determine whether the equation represents a direct varation. if it does, find the constant, find the constant variation. 2y = 5x

SVETLANKA909090 [29]

Is it 5x1?
or 5x+1 cause i'm confused

6 0

2 years ago

Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3

Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

$\frac{dV}{dt} = -kA$

Using Euler's method

$\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i} \\$

Where initial droplet volume is:

$V(0) = \frac{4pi}{3} * r(0)^3 = \frac{4pi}{3} * 2.5^3 = 65.45 mm^3$

Hence, the iterative solution will be as next:

i = 1, ti = 0, Vi = 65.45

$V'_{i} = -k *4pi*(\frac{3*65.45}{4pi})^(2/3) = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88$

i = 2, ti = 0.5, Vi = 63.88

$V'_{i} = -k *4pi*(\frac{3*63.88}{4pi})^(2/3) = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33$

i = 3, ti = 1, Vi = 62.33

$V'_{i} = -k *4pi*(\frac{3*62.33}{4pi})^(2/3) = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813$

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

$r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\$

The average change of droplet radius with time is:

Δr/Δt = $\frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min$

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

5 0

3 years ago

PLEASE HELP 20 POINTS PLEASE HELP BROOO

Ulleksa [173]

Answer: 31700 sq mi

Step-by-step explanation: Well in order to find out the sq mi for Lake Superior you will add 7340 and 24360 which equals 31700 sq mi.

7 0

2 years ago