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snow_tiger [21]
2 years ago
15

Quick pls!! my math grade is at a B! I need to raise it.

Mathematics
1 answer:
Leokris [45]2 years ago
5 0
I don’t know but I think it should be -04 I assume don’t know
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write tge equation for the following scenario. Then model and solve. Maria bought 5 jackets online.she paid $10 for shipping. if
Marizza181 [45]
If 5 jackets where bought and Maria paid $10 for shipping then each jacket would equal 12 because 12x5= 60+10= $70
3 0
3 years ago
The new club sticker is in the shape of a triangle. It has a height of 8 inches and a base of 10 inches. The area of the club st
rusak2 [61]

Answer:

40 square inches.

Step-by-step explanation:

It is given that the new club sticker is in the shape of a triangle.

Height of triangle = 8 inches

Base of triangle = 10 inches

We need to find the area of sticker.

Area of triangle =\dfrac{1}{2}\times base \times height

Substitute base = 10 and height = 8 in the above formula.

Area of triangle =\dfrac{1}{2}\times 10\times 8

Area of triangle =\dfrac{80}{2}

Area of triangle =40

Therefore, the area of the club sticker is 40 square inches.

5 0
3 years ago
What is the approximate 47? Give your answer and explain why it is correct. HELP
a_sh-v [17]

Answer:

7

Step-by-step explanation:

7 is approximate to \sqrt{47} because 7 is \sqrt{49}, and 49 is close to 47

3 0
3 years ago
Read 2 more answers
Kala has been offered two 40 hour a week jobs. One job pays an hourly wage of $25 and 10% of all sales. The other job pays $20 a
bazaltina [42]
(40 * 25) + 0.10x = (40 * 20) + 0.20x
1000 + 0.10x = 800 + 0.20x
1000 - 800 = 0.20x - 0.10x
200 = 0.10x
200/0.10 = x
2000 = x <=== weekly sales must be $ 2000
3 0
3 years ago
Could someone please help me out? I've tried to solve this but I'm really having some trouble with it. Please try to explain it
guajiro [1.7K]

To find the area of the shaded region you need find the area of the shaded region and subtract the area of the unshaded region.

Area of a rectangle = width x length

A = (x + 10) x (2x + 5)

Next apply FOIL or First Outer Inner Last

A = (x * 2x) (x * 5) (10 * 2x) (10 * 5)

A= 2x2 + 5x + 20x + 50

A= 2x2 +25x +50

 

Area of a square=  sides2

A= (x + 1)2

A= (x+1) (x+1)

Next apply FOIL or First Outer Inner Last

A = (x *x) (1*x) (1*x) (1*1)

A = x2 + 1x + 1x +1

A= x2 + 2x +1

 

A= 2x2 +25x +50 - 2x2 +25x +50

A= 50x + 100





4 0
3 years ago
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