Answer:
Option (d) outfile.write();
Explanation:
As the object created for the class BufferedWriter is outfile, outfile.write is the correct syntax for writing in a text file. Here, write is the method used for writing into a text file. The data present is written in the textfile. Here, the text file is opened before writing the text into the file. Option (d) is correct.
Option (a) outfile.newLine(); is used to separate the lines. This is used to break the existing lines into smaller lines. This can also be used to start a new line. Here, newLine() is the method.So, option (a) is not suitable.
Option (b) outfile.existLine(); This is not a valid syntax as there is no method called existLine() in the class BufferedWriter. So, this is a wrong option.
Option (c) Write(outfile); This is not a valid syntax for writing in a text file. This is a wrong option.
Technology changes advertising and communications by increasing the outreach of people that will get the message, and increasing the speed at which they get the message. Which in turn makes the advertising more relevent because they can release more product to a wider audience during a specific time period.
Go to your general settings and click on data usage and it should show you how much storage is left.
The answer is Tailoring the baseline to their needs.
After an organization selects applicable security control baseline but finds not all of the controls apply, it initiates a tailoring process to modify the controls appropriately and more closely with specific conditions related to organizational missions, information systems or environments of operation. It is an integral part of the security control selection and specification and involves risk management processes like assessing, responding to, and framing.
Answer:
See the code below and the algorithm explanation on the figure.
Explanation:
The explanation in order to get the answer is given on the figure below.
Solving this problem with C. The program is given below:
#include <stdio.h>
int main(void) {
int n, Even=0, Odd=0, Zeros=0;
for (;;) {
printf("\nEnter the value the value that you want to check(remember just integers): ");
//IF we input a non-numeric character the code end;
if (scanf("%d", &n) != 1) break;
if (n == 0) {
Zeros++;
}
else {
if (n % 2) {
Even++;
}
else {
Odd++;
}
}
}
printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);
return 0;
}
