Answer:
Create a dynamic-sized circularly-linked list to hold a tuple of the adverts and the count. As the program runs, the sum of the counts is used to calculate the fixed advertisement time which is saved in a variable time_slot. Then a loop statement should be used to traversal the linked list continuously until the count sum is exhausted for the day.
Explanation:
A circularly-linked list is a linked list with both ends joined together. With this data structure, the continuous traversal of the list is easier and faster. A conditional statement is used in the algorithm to check and decrement the count of each advert and when all is zero or false, the program ends.
Answer:
Explanation:
Let's do this in Python, first we need to convert the number into string in order to break it into a list of character, then we can replace the kth character with d. Finally we join all characters together, convert it to integer then output it
def setKthDigit(n, k, d):
n_string = str(n)
d_char = str(d)
n_char = [c for c in n_string]
n_char[k] = d_char
new_n_string = ''.join(n_char)
return int(new_n_string)
C operations section is where you would be working
the answer to this is 2 and 3
Hope this helped
-scav
Explanation:
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